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How much work does someone need to do if a crate moves 20 meters with force of 200 newtons?
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If a worker pushes horizontally on a large crate with a force of 298 newtons and the crate moved 6.5 meters how much work do he do?
Work = force x distance = Newtons x meters = 1937 Joules.
How much work is performed when a 25-kilogram crate is pushed 5 meters with a force of 15 newtons?
Work = (force) x (distance) = (15) x (5) = 75 joules.The mass of the crate is irrelevant.
How much work is performed when 100 kg crate is pushed 30 meters with a force of 40 newtons?
Multiply the force by the distance. The mass is irrelevant for this problem.
A simple machine such as a pulley is used to make work easier Erin used 50 newtons of force to lift a crate 3 meters She then tied the crate to a pulley and used the pulley to lift the crate again?
yes
A simple machine such as a pulley is used to make work easier. Erin used 50 newtons of force to lift a crate 3 meters. She then tied the crate to a pulley and used the pulley to lift the crate again.?
yes
If a worker pushes horizontally on a large crate with a force of 298 newtons and the crate moved 6.5 meters how much work do he do?
Work = force x distance = Newtons x meters = 1937 Joules.
How much work is performed when a 25-kilogram crate is pushed 5 meters with a force of 15 newtons?
Work = (force) x (distance) = (15) x (5) = 75 joules.The mass of the crate is irrelevant.
How much work is performed when 100 kg crate is pushed 30 meters with a force of 40 newtons?
Multiply the force by the distance. The mass is irrelevant for this problem.
What is the potential energy of a crate lifted with a force of 100 newtons a vertical distance of 2 meters?
Force x distance = 100 x 2 = 200 newton-meters = 200 joules.
A simple machine such as a pulley is used to make work easier Erin used 50 newtons of force to lift a crate 3 meters She then tied the crate to a pulley and used the pulley to lift the crate again?
yes
A simple machine such as a pulley is used to make work easier. Erin used 50 newtons of force to lift a crate 3 meters. She then tied the crate to a pulley and used the pulley to lift the crate again.?
yes
A boy exerts an average force of 65N when he lifts a box 1.2 meters How much work does he do?
Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.
A 33 kg crate rests on a horizontal floor and a 58 kg person is standing on the crate Determine the magnitude of the normal force that the floor exerts on the crate.?
891.8 newtons.
How much work is done if you push a 100N crate with friction of 70N across a 10m floor?
Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.
Calculate the work done to move a dresser 7 meters using a force of 2.5 newtons?
A force of 2.5 newtons acting through a distance of 7 meters delivers 17.5 newton meters = 17.5 joules of work.
What measurement do they use on force meters?
Newtons (N) or Pounds (lbs)
A 40kg crate is at rest on a level surface if the coefficient of static friction between the crate and the surface is 0.69 what horizontal force is required to get the crate moving?
276 Newtons. Coefficient of static friction is a ratio between the force it takes to budge the object over the normal force (mass times gravity). So: 0.69 = Force / 400 N (40 kg times 10 m/s^2, the force of gravity). Solve for 276 N.
