0
Fnet = F1+F2
Force of man f1 = 10n
Force of goat f2 = 10n
So,
Fnet = 10+10
Fnet=20n
================================
-- If Fred and the man are both pushing in the same direction, then
the net force is 20 newtons.
-- If they're not both pushing in the same direction, then the net force
is less than 20 N, but we don't have enough information to be able to
nail down either the net force or its direction.
What else can I help you with?
Where can one find a crate amp?
Crate amps can be found on the website Crate Amps. Guitar Center and Musicians Friend also sell crate amps. For a more economical priced amp, eBay has a selection of crate amps for auction.
A crate moves 10m to the right on a horizontal surface as a woman pulls on it with a 10-N force Rank the following situations shown below according to the work done by her force least to greatest?
The woman pulls on the crate, but the crate does not move. The woman pulls on the crate and it moves 5m to the right. The woman pulls on the crate and it moves 10m to the right. The woman pulls on the crate and it moves 15m to the right. So, ranking from least to greatest work done by her force would be 1, 2, 3, 4.
If a crate accelerates at 2.5 m5 and if the net force exerted is about 500N what is the mass of the crate?
In accordance to Newton's Second Law, you need to divide the force by the acceleration. The answer in this case will be in kilograms.
If a crate is stationary on an incline does it mean that it is in the state of equilibrium?
If a crate placed on an inclined plane is moving at constant velocity or not moving at all -- which is really a special case of constant velocity where the velocity is zero -- then the sum of the forces acting upon it is zero. We can say that it is in a state of equilibrium, where all forces acting upon it are in perfect balance and cancel themselves out. A free-body diagram is often used to represent a body and the forces acting upon it and helps us visualize the relationship of the vector forces. See this link: http://en.wikipedia.org/wiki/Free-body_diagram#Example
How much work did the movers do horizontally pushing a 150 kg crate 10.4 m across a rough floor without acceleration if the effective coefficient of friction was 0.70?
The work done by the movers can be calculated using the work-energy principle. The work done can be found by multiplying the force of friction by the distance the crate was moved. The force of friction is the product of the coefficient of friction and the normal force (weight of the crate). The work done will be equal to the force of friction multiplied by the distance moved.
If a worker pushes horizontally on a large crate with a force of 298 newtons and the crate moved 6.5 meters how much work do he do?
Work = force x distance = Newtons x meters = 1937 Joules.
A boy pushing forward on a crate with a force of 100 newtons the reaction force is?
The reaction force is 100 newtons exerted by the crate on the boy in the opposite direction (Newton's third law).
How much work is performed when a 25-kilogram crate is pushed 5 meters with a force of 15 newtons?
The work done is calculated as the force applied multiplied by the distance traveled in the direction of the force. In this case, the work done is 75 Joules (15 N * 5 m) when pushing the 25 kg crate with a force of 15 Newtons over a distance of 5 meters.
How much work does someone need to do if a crate moves 20 meters with force of 200 newtons?
The work done on the crate would be 4000 joules (W = F x d), as work is the product of force (200 N) and distance (20 m).
A simple machine such as a pulley is used to make work easier Erin used 50 newtons of force to lift a crate 3 meters She then tied the crate to a pulley and used the pulley to lift the crate again?
By using a pulley, Erin can reduce the amount of force needed to lift the crate. If Erin uses a single fixed pulley, she would still need to apply 50 newtons of force to lift the crate, but it would require less physical effort due to the change in direction of the force. If she uses a more complex pulley system, like a block and tackle, she could further reduce the amount of force needed, making it even easier to lift the crate.
What is the potential energy of a crate lifted with a force of 100 newtons a vertical distance of 2 meters?
Force x distance = 100 x 2 = 200 newton-meters = 200 joules.
a pulley system uses a 250-N force to lift a 2,740-N crate, What is the mechanical advantage of the system?
Answer: Mechanical advantage can be achieved just by adding more loops or pulleys. It is given that to lift a crate, a pulley system exerts a force of 2,740 newtons. It is required to find the mechanical advantage of the pulley system if the input force is 250 newtons What is the mechanical advantage of the pulley system if the exerted force changes from 2,740 newtons to 250 newtons? As if the force does some work, it increases the distance. Mechanical advantage does nothing with the number of pulleys. It only depends on the weight that is to be lift. Also, F1/F2 = 2740/250 = 10.96 The multiple pulleys create mechanical advantage. It can be achieved just by adding more loops or pulleys. Therefore, Mechanical advantage can be achieved just by adding more loops or pulleys.
If 68 joules of work were necessary to move a 4 newton crate how far was the crate moved?
The work done is given by the formula Work = Force x Distance. Rearranging this formula we find Distance = Work / Force. Plugging in the values given, we get Distance = 68 joules / 4 newtons = 17 meters. So, the crate was moved 17 meters.
A simple machine such as a pulley is used to make work easier. Erin used 50 newtons of force to lift a crate 3 meters. She then tied the crate to a pulley and used the pulley to lift the crate again.?
yes
When a person pushes a crate across the floor what is the effect?
The person's push creates a force that accelerates the crate. As long as the force overcomes friction, the crate will move across the floor.
What is the acceleration of the 25 kg crate which is pulled by a rope along a frictionless surface at an angle of 30 degrees above the horizontal if the tension on the rope is 120 N?
the force acting down the slope = sin 30 * 25 (kg) = 0.5 * 25 = 12.5 kg = (12.5 * 9.806 ) 122.575 newtons = resultant force of (122.575-120 ) 2.575 newtons downhill giving downhill acceleration of (using f=ma) 0.103 (m/s)/s
When an object is in equilibrium according to its component forces?
Interpreting the question as follows... "When is an object in equilibrium according to its component forces?"When all component forces cancel leaving no resultant force.For example - If Joe pulls on a crate with a force of 10 Newtons North, and Sally pulls on the same crate at the same time with a force of 10 Newtons South then all of the component forces combine to give a resultant force of zero. Thus the crate is in equilibrium. Math: 10 + (-10) = 0
