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When a person pushes a crate across the floor what force is working in reaction to the pushing force?
The force that resists the motion of the crate is the force of friction between the crate and the floor. This frictional force acts in the opposite direction to the pushing force applied by the person, making it harder to move the crate.
A 1500 N crate is being pushed across a level floor at a constant speed. What will be the acceleration of the crate?
The acceleration of the crate will be zero since it is moving at a constant speed. This means that the net force acting on the crate is zero, so the forces pushing it forward are balanced by the forces resisting its motion.
How much work is performed when a 25-kilogram crate is pushed 5 meters with a force of 15 newtons?
The work done is calculated as the force applied multiplied by the distance traveled in the direction of the force. In this case, the work done is 75 Joules (15 N * 5 m) when pushing the 25 kg crate with a force of 15 Newtons over a distance of 5 meters.
How much work is performed when 100 kg crate is pushed 30 meters with a force of 40 newtons?
Multiply the force by the distance. The mass is irrelevant for this problem.
Once the crate is sliding how hard do you push to keep is moving at constant valocity?
You should push with a force equal to the force of friction acting on the crate. This will counteract the friction force and allow the crate to continue moving at a constant velocity. Pushing with a greater force will accelerate the crate, while pushing with a force lower than the frictional force will cause it to decelerate.
When a person pushes a crate across the floor what force is working in reaction to the pushing force?
The force that resists the motion of the crate is the force of friction between the crate and the floor. This frictional force acts in the opposite direction to the pushing force applied by the person, making it harder to move the crate.
If a man pushes on a crate with 10 newtons of force and Fred the goat pushes with him with another 10 Newtons of force what is the net force of Fred and the man on the crate?
Fnet = F1+F2Force of man f1 = 10nForce of goat f2 = 10nSo,Fnet = 10+10Fnet=20n================================-- If Fred and the man are both pushing in the same direction, thenthe net force is 20 newtons.-- If they're not both pushing in the same direction, then the net forceis less than 20 N, but we don't have enough information to be able tonail down either the net force or its direction.
A 1500 N crate is being pushed across a level floor at a constant speed. What will be the acceleration of the crate?
The acceleration of the crate will be zero since it is moving at a constant speed. This means that the net force acting on the crate is zero, so the forces pushing it forward are balanced by the forces resisting its motion.
How much work is performed when a 25-kilogram crate is pushed 5 meters with a force of 15 newtons?
The work done is calculated as the force applied multiplied by the distance traveled in the direction of the force. In this case, the work done is 75 Joules (15 N * 5 m) when pushing the 25 kg crate with a force of 15 Newtons over a distance of 5 meters.
If you push on a heavy crate to the right and it slides what is the direction of friction on the crate?
The direction of friction on the crate is opposite to the direction in which it is sliding. In this case, since you are pushing the crate to the right, the friction will act to the left in order to oppose the motion.
How much work is performed when 100 kg crate is pushed 30 meters with a force of 40 newtons?
Multiply the force by the distance. The mass is irrelevant for this problem.
Once the crate is sliding how hard do you push to keep is moving at constant valocity?
You should push with a force equal to the force of friction acting on the crate. This will counteract the friction force and allow the crate to continue moving at a constant velocity. Pushing with a greater force will accelerate the crate, while pushing with a force lower than the frictional force will cause it to decelerate.
If a worker pushes horizontally on a large crate with a force of 298 newtons and the crate moved 6.5 meters how much work do he do?
Work = force x distance = Newtons x meters = 1937 Joules.
If we push a crate at a constant velocity how do we know how much friction acts on the crate compared to our pushing force?
If the crate is moving at a constant velocity, then the force of friction acting on the crate is equal in magnitude and opposite in direction to the force you are applying to push the crate. This means that the force you apply to push the crate is balancing out the force of friction acting against it. By measuring the force you are exerting and observing the constant velocity of the crate, you can infer the magnitude of the friction force.
If you push a crate with a force of 100 N and it slides at a constant velocity how much is the friction acting on the crate?
If the crate is moving at a constant velocity, the friction force is equal in magnitude but opposite in direction to the pushing force, so it is also 100 N. This is because the two forces are balanced and there is no net force acting on the crate.
A crate remains at rest on a factory floor while you push on it with a horizontal force F How big is the friction force exerted on the crate by the floor?
The friction force exerted on the crate by the floor is equal in magnitude but opposite in direction to the pushing force you apply to the crate. If the crate is not moving, the friction force is static friction, and it adjusts its magnitude to exactly match the applied force to keep the crate at rest.
A simple machine such as a pulley is used to make work easier Erin used 50 newtons of force to lift a crate 3 meters She then tied the crate to a pulley and used the pulley to lift the crate again?
By using a pulley, Erin can reduce the amount of force needed to lift the crate. If Erin uses a single fixed pulley, she would still need to apply 50 newtons of force to lift the crate, but it would require less physical effort due to the change in direction of the force. If she uses a more complex pulley system, like a block and tackle, she could further reduce the amount of force needed, making it even easier to lift the crate.
