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If the crate is moving at a constant velocity, the friction force is equal in magnitude but opposite in direction to the pushing force, so it is also 100 N. This is because the two forces are balanced and there is no net force acting on the crate.

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1y ago

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When a crate slide down an incline at a constant velocity it is?

When a crate slides down an incline at a constant velocity, it is experiencing a balanced force situation. The force of gravity pulling it downhill is counteracted by the force of friction acting in the opposite direction. This results in the crate moving steadily without speeding up or slowing down.


How would the velocity of the book change if the applied force were equal to the sliding friction force?

If the applied force were equal to the sliding friction force, the book would move at a constant velocity since the two forces would be balanced. This means there would be no acceleration or deceleration, and the book's velocity would remain unchanged as long as the forces stayed in equilibrium.


As a block slides across a horizontal surface with constant velocity describe the changes of the energy that would occur within the block.?

As the block slides with constant velocity, its kinetic energy remains constant. The work done by friction converts some of this energy into heat, resulting in a decrease in the block's internal energy. Overall, the total mechanical energy (sum of kinetic and potential energy) of the block does not change.


Can A hockey puck that slides across the ice at a constant speed be in equilibrium?

Yes, a hockey puck sliding across the ice at a constant speed can be considered to be in dynamic equilibrium. While the puck is moving, the forces acting on it are balanced, resulting in no acceleration in its velocity.


What is the force of friction acting on a crate that slides across the floor?

The force of friction acting on a crate sliding across the floor is equal in magnitude but opposite in direction to the force applied to move the crate. It depends on the coefficient of friction between the crate and the floor, as well as the weight of the crate.

Related Questions

When a crate slide down an incline at a constant velocity it is?

When a crate slides down an incline at a constant velocity, it is experiencing a balanced force situation. The force of gravity pulling it downhill is counteracted by the force of friction acting in the opposite direction. This results in the crate moving steadily without speeding up or slowing down.


How would the velocity of the book change if the applied force were equal to the sliding friction force?

If the applied force were equal to the sliding friction force, the book would move at a constant velocity since the two forces would be balanced. This means there would be no acceleration or deceleration, and the book's velocity would remain unchanged as long as the forces stayed in equilibrium.


As a block slides across a horizontal surface with constant velocity describe the changes of the energy that would occur within the block.?

As the block slides with constant velocity, its kinetic energy remains constant. The work done by friction converts some of this energy into heat, resulting in a decrease in the block's internal energy. Overall, the total mechanical energy (sum of kinetic and potential energy) of the block does not change.


Can A hockey puck that slides across the ice at a constant speed be in equilibrium?

Yes, a hockey puck sliding across the ice at a constant speed can be considered to be in dynamic equilibrium. While the puck is moving, the forces acting on it are balanced, resulting in no acceleration in its velocity.


A 300 kg bear grasping a vertical tree slides down at constant velocity The friction force between the bear and tree is how many neutrons?

According to Newton's second law, F=ma. That is, the bear's acceleration should be proportional to the total force acting on the bear. As the bear's velocity is constant, its acceleration is zero. Therefore, the total Force acting on the bear is zero. Thus, the friction has to be equal in magnitude and opposite in direction to the bear's weight. As W=mg, we get that its weight is 9.8*400=3,920 Newton. Thus, the friction acting on the bear is 3,920 Newton upwards.


What is the force of friction acting on a crate that slides across the floor?

The force of friction acting on a crate sliding across the floor is equal in magnitude but opposite in direction to the force applied to move the crate. It depends on the coefficient of friction between the crate and the floor, as well as the weight of the crate.


What is the force of friction when a crate slides across the floor?

The force of friction when a crate slides across the floor is dependent on the coefficient of friction between the crate and the floor, as well as the normal force acting on the crate. The frictional force resists the motion of the crate and can be calculated using the equation: frictional force = coefficient of friction * normal force.


Why do objects slide?

Objects slide because of the forces acting upon them, such as gravity or friction. When an object is on a sloped surface, gravity pulls it downward, causing it to move. The presence of friction between the object and the surface affects how easily the object slides.


Pull horizontally on a crate with a force of 140 N and it slides across the floor in a dynamic equilibrium How much friction is acting on the crate?

If the crate isn't accelerating ... i.e. sliding at a constant speed, not speeding up or slowing down ...then the forces on it are balanced. The pseudo-force of friction is 140N in the direction opposite toits speed.


A 2.0 kg wood box slides down a vertical wood wall while you push on it at a 45 angle. What is the force applied to slide the box down at a constant speed?

The force applied to slide the box down at a constant speed is equal to the force of kinetic friction acting against the box. This force is given by the equation: friction force = coefficient of kinetic friction * normal force. Since the box is sliding down the wall, the normal force is equal to the weight of the box. Therefore, the force applied is equal to the coefficient of kinetic friction * weight of the box.


Predict the effect that significant friction would have on the acceleration of the box as it slides down the incline. Explain the cause of the predicted effect?

Significant friction would decrease the acceleration of the box as it slides down the incline. Friction opposes the motion of the box by creating a force that acts opposite to the direction of motion. This force would reduce the net force acting on the box, leading to a decrease in acceleration.


Is a hockey puck at equilibrium if it slides across the ice at a constant speed?

Yes, a hockey puck sliding across the ice at a constant speed is in equilibrium. The forces acting upon it are balanced, with no net force causing acceleration.