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What is the force of friction when a crate slides across the floor?
The force of friction when a crate slides across the floor is dependent on the coefficient of friction between the crate and the floor, as well as the normal force acting on the crate. The frictional force resists the motion of the crate and can be calculated using the equation: frictional force = coefficient of friction * normal force.
If you push a crate with a force of 100 N and it slides at a constant velocity how much is the friction acting on the crate?
If the crate is moving at a constant velocity, the friction force is equal in magnitude but opposite in direction to the pushing force, so it is also 100 N. This is because the two forces are balanced and there is no net force acting on the crate.
Pull horizontally on a crate with a force of 140 N and it slides across the floor in a dynamic equilibrium How much friction is acting on the crate?
If the crate isn't accelerating ... i.e. sliding at a constant speed, not speeding up or slowing down ...then the forces on it are balanced. The pseudo-force of friction is 140N in the direction opposite toits speed.
If you push a crate across a factory floor at constant speed in a constant direction what is the magnitude of the force of friction on the crate compared with your push?
The magnitude of the force of friction on the crate would be equal to the magnitude of your push. This is because the crate is moving at a constant speed, indicating that the force you are applying is balanced by the force of friction acting in the opposite direction.
If we push a crate at a constant velocity how do we know how much friction acts on the crate compared to our pushing force?
If the crate is moving at a constant velocity, then the force of friction acting on the crate is equal in magnitude and opposite in direction to the force you are applying to push the crate. This means that the force you apply to push the crate is balancing out the force of friction acting against it. By measuring the force you are exerting and observing the constant velocity of the crate, you can infer the magnitude of the friction force.
What is the force of friction when a crate slides across the floor?
The force of friction when a crate slides across the floor is dependent on the coefficient of friction between the crate and the floor, as well as the normal force acting on the crate. The frictional force resists the motion of the crate and can be calculated using the equation: frictional force = coefficient of friction * normal force.
If you push a crate with a force of 100 N and it slides at a constant velocity how much is the friction acting on the crate?
If the crate is moving at a constant velocity, the friction force is equal in magnitude but opposite in direction to the pushing force, so it is also 100 N. This is because the two forces are balanced and there is no net force acting on the crate.
Pull horizontally on a crate with a force of 140 N and it slides across the floor in a dynamic equilibrium How much friction is acting on the crate?
If the crate isn't accelerating ... i.e. sliding at a constant speed, not speeding up or slowing down ...then the forces on it are balanced. The pseudo-force of friction is 140N in the direction opposite toits speed.
If you push on a heavy crate to the right and it slides what is the direction of friction on the crate?
The direction of friction on the crate is opposite to the direction in which it is sliding. In this case, since you are pushing the crate to the right, the friction will act to the left in order to oppose the motion.
If you push a crate across a factory floor at constant speed in a constant direction what is the magnitude of the force of friction on the crate compared with your push?
The magnitude of the force of friction on the crate would be equal to the magnitude of your push. This is because the crate is moving at a constant speed, indicating that the force you are applying is balanced by the force of friction acting in the opposite direction.
If we push a crate at a constant velocity how do we know how much friction acts on the crate compared to our pushing force?
If the crate is moving at a constant velocity, then the force of friction acting on the crate is equal in magnitude and opposite in direction to the force you are applying to push the crate. This means that the force you apply to push the crate is balancing out the force of friction acting against it. By measuring the force you are exerting and observing the constant velocity of the crate, you can infer the magnitude of the friction force.
When a crate slide down an incline at a constant velocity it is?
When a crate slides down an incline at a constant velocity, it is experiencing a balanced force situation. The force of gravity pulling it downhill is counteracted by the force of friction acting in the opposite direction. This results in the crate moving steadily without speeding up or slowing down.
What force is needed to slide a 250-kg crate across the floor at constant velocity if the coefficient of sliding friction between a crate and a horizontal floor is 0.25?
The force needed to slide the crate at constant velocity is equal in magnitude but opposite in direction to the force of friction. The force of friction can be calculated as the product of the coefficient of friction and the normal force acting on the crate (weight of the crate). Therefore, the force needed would be 250 kg * 9.8 m/s^2 * 0.25 = 612.5 N.
When a person pushes a crate across the floor what is the effect?
The person's push creates a force that accelerates the crate. As long as the force overcomes friction, the crate will move across the floor.
What 4 forces act on an object as it slides across the floor?
You should have friction between the box and the ground, the force you used to push it, the mass of the object, and gravity. The resistance of the air is neglibible. This should be all the forces on an object on flat ground.
What equations is most useful for solving a problem that asks for the distance a fast-moving crate slides across a factory floor in coming to a stop?
The most useful equation for solving this problem is likely the equation for kinetic energy: KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the crate, and v is the initial velocity of the crate. This equation can be used to find the work done by friction to bring the fast-moving crate to a stop. Applying the work-energy principle can then help determine the distance the crate slides before coming to a stop.
If you push a crate across a factory floor at constant speed in a constant directionwhat is the magnitude of the force of friction on the crate compared with your push?
The magnitude of the force of friction on the crate is equal and opposite to the force you apply to push it, as long as the crate is moving at constant speed. This is because the force of friction balances the push force to prevent acceleration.
