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The force of friction when a crate slides across the floor is dependent on the coefficient of friction between the crate and the floor, as well as the normal force acting on the crate. The frictional force resists the motion of the crate and can be calculated using the equation: frictional force = coefficient of friction * normal force.
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What is the force of friction acting on a crate that slides across the floor?
The force of friction acting on a crate sliding across the floor is equal in magnitude but opposite in direction to the force applied to move the crate. It depends on the coefficient of friction between the crate and the floor, as well as the weight of the crate.
When a person pushes a crate across the floor what is the effect?
The person's push creates a force that accelerates the crate. As long as the force overcomes friction, the crate will move across the floor.
When a person pushes a crate across the floor what force is working in reaction to the pushing force?
The force that resists the motion of the crate is the force of friction between the crate and the floor. This frictional force acts in the opposite direction to the pushing force applied by the person, making it harder to move the crate.
A crate remains at rest on a factory floor while you push on it with a horizontal force F How big is the friction force exerted on the crate by the floor?
The friction force exerted on the crate by the floor is equal in magnitude but opposite in direction to the pushing force you apply to the crate. If the crate is not moving, the friction force is static friction, and it adjusts its magnitude to exactly match the applied force to keep the crate at rest.
If you push a crate across a factory floor at constant speed in a constant direction what is the magnitude of the force of friction on the crate compared with your push?
The magnitude of the force of friction on the crate would be equal to the magnitude of your push. This is because the crate is moving at a constant speed, indicating that the force you are applying is balanced by the force of friction acting in the opposite direction.
What is the force of friction acting on a crate that slides across the floor?
The force of friction acting on a crate sliding across the floor is equal in magnitude but opposite in direction to the force applied to move the crate. It depends on the coefficient of friction between the crate and the floor, as well as the weight of the crate.
When a person pushes a crate across the floor what is the effect?
The person's push creates a force that accelerates the crate. As long as the force overcomes friction, the crate will move across the floor.
When a person pushes a crate across the floor what force is working in reaction to the pushing force?
The force that resists the motion of the crate is the force of friction between the crate and the floor. This frictional force acts in the opposite direction to the pushing force applied by the person, making it harder to move the crate.
A crate remains at rest on a factory floor while you push on it with a horizontal force F How big is the friction force exerted on the crate by the floor?
The friction force exerted on the crate by the floor is equal in magnitude but opposite in direction to the pushing force you apply to the crate. If the crate is not moving, the friction force is static friction, and it adjusts its magnitude to exactly match the applied force to keep the crate at rest.
If you push a crate across a factory floor at constant speed in a constant directionwhat is the magnitude of the force of friction on the crate compared with your push?
The magnitude of the force of friction on the crate is equal and opposite to the force you apply to push it, as long as the crate is moving at constant speed. This is because the force of friction balances the push force to prevent acceleration.
If you push a crate across a factory floor at constant speed in a constant direction what is the magnitude of the force of friction on the crate compared with your push?
The magnitude of the force of friction on the crate would be equal to the magnitude of your push. This is because the crate is moving at a constant speed, indicating that the force you are applying is balanced by the force of friction acting in the opposite direction.
What force is needed to slide a 250-kg crate across the floor at constant velocity if the coefficient of sliding friction between a crate and a horizontal floor is 0.25?
The force needed to slide the crate at constant velocity is equal in magnitude but opposite in direction to the force of friction. The force of friction can be calculated as the product of the coefficient of friction and the normal force acting on the crate (weight of the crate). Therefore, the force needed would be 250 kg * 9.8 m/s^2 * 0.25 = 612.5 N.
Pull horizontally on a crate with a force of 140 N and it slides across the floor in a dynamic equilibrium How much friction is acting on the crate?
If the crate isn't accelerating ... i.e. sliding at a constant speed, not speeding up or slowing down ...then the forces on it are balanced. The pseudo-force of friction is 140N in the direction opposite toits speed.
What equations is most useful for solving a problem that asks for the distance a fast-moving crate slides across a factory floor in coming to a stop?
The most useful equation for solving this problem is likely the equation for kinetic energy: KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the crate, and v is the initial velocity of the crate. This equation can be used to find the work done by friction to bring the fast-moving crate to a stop. Applying the work-energy principle can then help determine the distance the crate slides before coming to a stop.
How do you solve a 200-lb crate lies on the floor. The coefficient of static friction between the crate and the floor is 0.60. What is the minimum force required to start the crate sliding?
To calculate the minimum force required to start the crate sliding, you would multiply the weight of the crate by the coefficient of static friction. In this case, 200 lb crate * 0.60 static friction coefficient = 120 lb minimum force needed to start the crate sliding.
What 4 forces act on an object as it slides across the floor?
You should have friction between the box and the ground, the force you used to push it, the mass of the object, and gravity. The resistance of the air is neglibible. This should be all the forces on an object on flat ground.
You are pushing a kg wooden crate across the floor. the force of sliding friction on the crate is 90 N. how much force must you exert on the crate to keep it moving with a constant velocity?
To keep the crate moving with constant velocity, the force you exert must balance the force of sliding friction. In this case, you must exert a force of 90 N in the opposite direction of the sliding friction, so the net force on the crate is zero and it remains in motion at a constant velocity.
