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How much work must be done on a 10 kg bicycle to increase its speed from 2 ms to 3 ms?
Wiki User
∙ 13y ago
30 J
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoThe bicycle's initial kinetic energy is [ ½ M Vi2 ], and its final kinetic energy is [ ½ M Vf2 ].
The difference in energy is the work that somebody from the outside has to put into it.
The difference is [ (final kinetic energy) minus (initial kinetic energy) ]
[ ½ M Vf2 ] minus [½ M Vi2 ]
or [ ½ M ] times [ Vf2 - Vi2 ]
=[ 5 ] x [ 102 - 52 ]
= [ 5 ] x [ 100 - 25 ]
= [ 5 ] x [ 75 ]
= 375 joules
Wiki User
∙ 13y agoThe bicycle's initial kinetic energy is [ ½ M Vi2 ], and its final kinetic energy is [ ½ M Vf2 ].
The difference in energy is the work that somebody from the outside has to put into it.
The difference is [ (final kinetic energy) minus (initial kinetic energy) ]
[ ½ M Vf2 ] minus [½ M Vi2 ]
or [ ½ M ] times [ Vf2 - Vi2 ] = [ 2.5 ] x [ 152 - 102 ]
= [ 2.5 ] x [ 225 - 100 ] = [ 2.5 ] x [ 125 ]
= 312.5 joules
Wiki User
∙ 13y agoKinetic Energy = 1/2 m V2
At 2 m/s, the bicycle's KE is (1/2 x 10 x 4) = 20 joules.
At 3 m/s, its KE is (1/2 x 10 x 9) = 45 joules.
The difference in kinetic energy at the higher speed is (45 - 20) = 25 joules.
That's the energy (work) that has to come from somewhere in order to achieve
the higher speed.
Check:
The ratio of speeds is 3/2 = 1.5 . Since kinetic energy is proportional to the square of the speed,
we need the square of the ratio to check. It's (1.5)2 = 2.25 .
The ratio of the kinetic energies that we calculated at the two speeds is (45/20) = 2.25 .
That's good enough for us. Check ! and mate
Wiki User
∙ 14y ago100 J
Anonymous
2 Nand the output force 4 N is it’s mechanical advantage
Anonymous
1000
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How much work must be done on a 10-kg bicycle to increase its speed from 5 m s to 10 m s?
375 Js (((((((((((: this is the right answer
How much work must be done on a 10kg bicycle to increase its speed from 2 M's to 3 M's?
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
How much work must be done on a 10 kg bicycle to increase its speed form 5 ms to 10 ms?
The work done on the bicycle is equal to the change in kinetic energy. The change in kinetic energy is given by 1/2 * m * (vf^2 - vi^2), where m is the mass of the bicycle, vf is the final velocity, and vi is the initial velocity. Plugging in the values, the work done is 625 J.
How much work must be done on a kg sled to increase its speed from 10ms to 15 ms?
To calculate the work done on the sled to increase its speed, you need to know the initial and final kinetic energy. The work done is equal to the change in kinetic energy, which is given by the formula: Work = (1/2) * m * (vf^2 - vi^2) Substitute the mass of the sled, initial speed, and final speed to find the work done.
Why was the invention of the multi-speed bicycle important?
The invention of the multi-speed bicycle increased the usefulness of the vehicle. It made it easier to pedal up hills giving it much more range.
How much work is done to increase a 20 kg scooters speed from 10 ms to 20 ms?
3000j
How much work must be done on a 5-kg sled to increase its speed from 10 m/s to 15 m/s?
312.5 J
How much work must be done on a 5-kg snowboard to increase its speed from 2 m s to 4 m s?
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How much work is done to increase a 20-kg scooter's speed from 10 m/s to 20 m/s?
3000 J *Shelby Sarah*
How much work must be done on a 20-kg go-cart to increase its speed from 5 m/s to 10 m/s?
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How much work is done to increase a 20 kg scooter speed from Ms to 20 ms?
The work done to increase the speed of the scooter can be calculated as the change in kinetic energy. The initial kinetic energy is given by (1/2)mv^2. The final kinetic energy is (1/2)m(20)^2. The work done is the difference between the final and initial kinetic energies.
How much work is done to increase a 20 kg scooter's speed from 10 ms to 20 ms?
The work done is equal to the change in kinetic energy, which can be calculated using the formula: W = ΔKE = 1/2 m (v_f^2 - v_i^2). Plugging in the values, the work done to increase the speed of the scooter from 10 m/s to 20 m/s is 6000 J.
