The work done is equal to the change in kinetic energy, which can be calculated using the formula: W = ΔKE = 1/2 m (v_f^2 - v_i^2). Plugging in the values, the work done to increase the speed of the scooter from 10 m/s to 20 m/s is 6000 J.
To calculate the work done on the sled to increase its speed, you need to know the initial and final kinetic energy. The work done is equal to the change in kinetic energy, which is given by the formula: Work = (1/2) * m * (vf^2 - vi^2) Substitute the mass of the sled, initial speed, and final speed to find the work done.
The work done to increase the speed of the scooter can be calculated as the change in kinetic energy. The initial kinetic energy is given by (1/2)mv^2. The final kinetic energy is (1/2)m(20)^2. The work done is the difference between the final and initial kinetic energies.
The work done on the snowboard to increase its speed is 100 Joules. This work-energy theorem is based on the change in kinetic energy, given by the equation: work = change in kinetic energy. In this case, the snowboard has a mass of 10 kg and the speed increases from 2 m/s to 4 m/s.
The work done to increase the speed of an object is equal to the change in its kinetic energy. The change in kinetic energy can be calculated using the formula ΔKE = 0.5 * m * (vf^2 - vi^2), where m is the mass of the object, vf is the final velocity, and vi is the initial velocity. Substituting the given values, the work done on a 1000-kg car to increase its speed from 1 m/s to 2 m/s would be ΔKE = 0.5 * 1000 * (2^2 - 1^2) = 1000 J.
Probably less then solving this question or since F=ma 72N. The N stands for Nitwick.
3000j
To calculate the work done on the sled to increase its speed, you need to know the initial and final kinetic energy. The work done is equal to the change in kinetic energy, which is given by the formula: Work = (1/2) * m * (vf^2 - vi^2) Substitute the mass of the sled, initial speed, and final speed to find the work done.
I have owned both of these scooters and the pro scooters are much better, That's why they cost more than slam scooters.
50cc scooters are restricted to around 30mph here in the UK. They can be de-reg'd up by a few mph but you'll notgenerally get much more out of them. Weight and stuff are also factors.
30 J
312.5 J
375 Js (((((((((((: this is the right answer
3000 J *Shelby Sarah*
750 j
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
The work done to increase the speed of the scooter can be calculated as the change in kinetic energy. The initial kinetic energy is given by (1/2)mv^2. The final kinetic energy is (1/2)m(20)^2. The work done is the difference between the final and initial kinetic energies.
$70