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How much work must be done on a 1000-kg car to increase its speed from 1 ms to 2 ms?
1,500 J
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How much work must be done on a kg sled to increase its speed from 10ms to 15 ms?
To calculate the work done on the sled to increase its speed, you need to know the initial and final kinetic energy. The work done is equal to the change in kinetic energy, which is given by the formula: Work = (1/2) * m * (vf^2 - vi^2) Substitute the mass of the sled, initial speed, and final speed to find the work done.
How much work must be done on a 1000kg car to increase its speed from 1ms to 2ms?
Initially energy of body will be: E=0.5mv^2 E=0.5*875*44^2 FInnally its energy will be: E=0.5*875*22^2 So loss in energy of body: E2-E1=0.5*875(44^2-22^2) SO this much energy is lost by the body if its speed is reduced to 22m/s. So we will have to do work equivalent to change energy to reduce its Energy. Work=E2-E1 Plz do the calculations
How much work is done to increase a 20 kg scooter's speed from 10 ms to 20 ms?
The work done is equal to the change in kinetic energy, which can be calculated using the formula: W = ΔKE = 1/2 m (v_f^2 - v_i^2). Plugging in the values, the work done to increase the speed of the scooter from 10 m/s to 20 m/s is 6000 J.
How much work is done to increase a 20 kg scooter speed from Ms to 20 ms?
The work done to increase the speed of the scooter can be calculated as the change in kinetic energy. The initial kinetic energy is given by (1/2)mv^2. The final kinetic energy is (1/2)m(20)^2. The work done is the difference between the final and initial kinetic energies.
How much work must be done on a 10-kg snowboard to increase its speed from 2ms to 4 ms 100 J.?
The work done on the snowboard to increase its speed is 100 Joules. This work-energy theorem is based on the change in kinetic energy, given by the equation: work = change in kinetic energy. In this case, the snowboard has a mass of 10 kg and the speed increases from 2 m/s to 4 m/s.
How much work must be done on a kg sled to increase its speed from 10ms to 15 ms?
To calculate the work done on the sled to increase its speed, you need to know the initial and final kinetic energy. The work done is equal to the change in kinetic energy, which is given by the formula: Work = (1/2) * m * (vf^2 - vi^2) Substitute the mass of the sled, initial speed, and final speed to find the work done.
How much work is done to increase a 20 kg scooters speed from 10 ms to 20 ms?
3000j
How much work must be done on a 1000kg car to increase its speed from 1ms to 2ms?
Initially energy of body will be: E=0.5mv^2 E=0.5*875*44^2 FInnally its energy will be: E=0.5*875*22^2 So loss in energy of body: E2-E1=0.5*875(44^2-22^2) SO this much energy is lost by the body if its speed is reduced to 22m/s. So we will have to do work equivalent to change energy to reduce its Energy. Work=E2-E1 Plz do the calculations
How much does a tonne weigh?
A tonne is 1000kg or 1000000g
How much work must be done on a 5-kg sled to increase its speed from 10 m/s to 15 m/s?
312.5 J
How much work must be done on a 5-kg snowboard to increase its speed from 2 m s to 4 m s?
30 J
How much work is done to increase a 20-kg scooter's speed from 10 m/s to 20 m/s?
3000 J *Shelby Sarah*
How much work must be done on a 20-kg go-cart to increase its speed from 5 m/s to 10 m/s?
750 j
How much work must be done on a 10-kg bicycle to increase its speed from 5 m s to 10 m s?
375 Js (((((((((((: this is the right answer
How much work must be done on a 10kg bicycle to increase its speed from 2 M's to 3 M's?
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
How much work is done to increase a 20 kg scooter's speed from 10 ms to 20 ms?
The work done is equal to the change in kinetic energy, which can be calculated using the formula: W = ΔKE = 1/2 m (v_f^2 - v_i^2). Plugging in the values, the work done to increase the speed of the scooter from 10 m/s to 20 m/s is 6000 J.
How much work is done to increase a 20 kg scooter speed from Ms to 20 ms?
The work done to increase the speed of the scooter can be calculated as the change in kinetic energy. The initial kinetic energy is given by (1/2)mv^2. The final kinetic energy is (1/2)m(20)^2. The work done is the difference between the final and initial kinetic energies.
