The equation of an inductor is ...
di/dt = L / V
... which means that the rate of change of current is proportional to voltage and inversely proportional to inductance.
Set this up in a sinusoidal forcing circuit and solve the differential equation, or use phasors, and you get ...
XL = 2 pi f L
... which means that inductive reactance is proportional to both frequency and inductance by the factor of 2 pi.
I have not included the derivation, because I don't know how to do it, and it does not seem necessary. If someone wants to provide one, please feel free to refine the answer.
943H
This isn't necessarily the case. It depends upon the value of resistance (which, at resonance, determines the current), and the values of the inductive- and capacitive-reactance.At resonance, the impedance of the circuit is equal to its resistance. This is because the vector sum of resistance, inductive reactance, and capacitive reactance, is equal the the resistance. This happens because, at resonance, the inductive- and capacitive-reactance are equal but opposite. Although they still actually exist, individually.If the resistance is low in comparison to the inductive and capacitive reactance, then the large current will cause a large voltage drop across the inductive reactance and a large voltage drop across the capacitive reactance. Because these two voltage drops are equal, but act the opposite sense to each other, the net reactive voltage drop is zero.So, at (series) resonance:a. the circuit's impedance is its resistance (Z = R)b. the current is maximumc. the voltage drop across the resistive component is equal to the supply voltaged. the voltage drop across the inductive-reactance component is the product of the supply current and the inductive reactancee. the voltage drop across the capacitive-reactance component is the product of the supply current and the capacitive reactancef. the voltage drop across both inductive- and capacitive-reactance is zero.
The reciprocal of reactance is susceptance, expressed in siemens.
a circuit in which inductance L,capacitance C and resistance R are connected in series and the circuit admits maximumum current corresponding to a given frequency of a.c.Another AnswerIn the case of a series circuit, resonance occurs when its inductive reactance is exactly equal to its capacitive reactance. As the vector sum of these two quantities will then be zero, the only opposition to current will be resistance and, so, maximum current will flow through the circuit when resonance occurs. ALL circuits can be made to resonate at what is called their 'resonant frequency' because, as frequency increases, the inductive reactance increases but capacitive reactance falls -so, at some point the two will equal each other, and resonance will occur.In my view resonance means - the condition that exists when the inductive reactance and the capacitive reactance are of equal magnitude, causing electrical energy to oscillate between the magnetic field of the inductor and the electric field of the capacitor.
for inductor, reactance XL = 2*pi* f *L, if frequency doubles then reactance increase. But for capacitor, reactance Xc = 1/(2*pi*f*C). In this case if frequency doubles the reactance decrease.
XL=2PifL is correct
reactance due to the capacitance of a capacitor or circuit,equal to the inverse of the product of the capacitance and the angular frequency.
943H
yesAnswerNo, but you can counter its effects. For example, if your load is inductive, then you can counter the effects of its inductive reactance by introducing capacitors with equal capacitive reactance.
Series resonance occurs when a circuit's inductive reactance is equal to its capacitive reactance. The resistance of the circuit is irrelevant.WebRep currentVote noRating noWeight
Inductive reactance, as well as capacitive reactance, is measured in ohms.
This isn't necessarily the case. It depends upon the value of resistance (which, at resonance, determines the current), and the values of the inductive- and capacitive-reactance.At resonance, the impedance of the circuit is equal to its resistance. This is because the vector sum of resistance, inductive reactance, and capacitive reactance, is equal the the resistance. This happens because, at resonance, the inductive- and capacitive-reactance are equal but opposite. Although they still actually exist, individually.If the resistance is low in comparison to the inductive and capacitive reactance, then the large current will cause a large voltage drop across the inductive reactance and a large voltage drop across the capacitive reactance. Because these two voltage drops are equal, but act the opposite sense to each other, the net reactive voltage drop is zero.So, at (series) resonance:a. the circuit's impedance is its resistance (Z = R)b. the current is maximumc. the voltage drop across the resistive component is equal to the supply voltaged. the voltage drop across the inductive-reactance component is the product of the supply current and the inductive reactancee. the voltage drop across the capacitive-reactance component is the product of the supply current and the capacitive reactancef. the voltage drop across both inductive- and capacitive-reactance is zero.
Inductive reactance.
With a series RLC circuit the same current goes through all three components. The reactance of the capacitor and inductor are equal and opposite at the resonant frequency, so they cancel out and the supply voltage appears across the resistor. This means that the current is at its maximum, but that current, flowing through the inductor and the capacitor, produces a voltage across each that is equal to the current times the reactance. The voltage magnification is the 'Q factor', equal to the reactance divided by the resistance.
The reciprocal of reactance is susceptance, expressed in siemens.
The symbol for inductive reactance is XL.
yes,they are equal at only one condition i.e. when the circuit containing R,L and C in series or in parallel behave as a purely resistive circuit. This condition occur only at resonance.