yes,they are equal at only one condition i.e. when the circuit containing R,L and C in series or in parallel behave as a purely resistive circuit. This condition occur only at resonance.
Resonance occurs in the circuit.
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Inductive reactance.
It isn't necessarily so. The capacitive voltage is the product of the current and capacitive reactance, while the inductive voltage is the product of the current and the inductive reactance. So it depends whether the capacitive reactance is greater or smaller than the inductive reactance!
Inductive reactance does NOT have it own sign or symbol. Rather, it uses Ohms as a quantifier. But Capacitive reactance ALSO uses Ohms as a quantifier. Fortunately, 1 Ohm of Inductive reactance is cancelled by 1 Ohm of Capacitive reactance at the same frequency of measurement.
Susceptance is the reciprocal of reactance, and is expressed in siemens (symbol: S). So, inductive susceptanceis the reciprocal of inductive reactance, and capacitive susceptance is the reciprocal of capacitive reactance.
Xc(capacitive reactance) = 1/(2piFC)XL(inductive reactance) = 2piFLWhere pi=3.14etc.,F=frequency and C and L are capacitance and inductance.Please pardon lack of proper symbology.
Inductive reactance.
Inductive reactance, as well as capacitive reactance, is measured in ohms.
It isn't necessarily so. The capacitive voltage is the product of the current and capacitive reactance, while the inductive voltage is the product of the current and the inductive reactance. So it depends whether the capacitive reactance is greater or smaller than the inductive reactance!
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Inductive reactance does NOT have it own sign or symbol. Rather, it uses Ohms as a quantifier. But Capacitive reactance ALSO uses Ohms as a quantifier. Fortunately, 1 Ohm of Inductive reactance is cancelled by 1 Ohm of Capacitive reactance at the same frequency of measurement.
Susceptance is the reciprocal of reactance, and is expressed in siemens (symbol: S). So, inductive susceptanceis the reciprocal of inductive reactance, and capacitive susceptance is the reciprocal of capacitive reactance.
This isn't necessarily the case. It depends upon the value of resistance (which, at resonance, determines the current), and the values of the inductive- and capacitive-reactance.At resonance, the impedance of the circuit is equal to its resistance. This is because the vector sum of resistance, inductive reactance, and capacitive reactance, is equal the the resistance. This happens because, at resonance, the inductive- and capacitive-reactance are equal but opposite. Although they still actually exist, individually.If the resistance is low in comparison to the inductive and capacitive reactance, then the large current will cause a large voltage drop across the inductive reactance and a large voltage drop across the capacitive reactance. Because these two voltage drops are equal, but act the opposite sense to each other, the net reactive voltage drop is zero.So, at (series) resonance:a. the circuit's impedance is its resistance (Z = R)b. the current is maximumc. the voltage drop across the resistive component is equal to the supply voltaged. the voltage drop across the inductive-reactance component is the product of the supply current and the inductive reactancee. the voltage drop across the capacitive-reactance component is the product of the supply current and the capacitive reactancef. the voltage drop across both inductive- and capacitive-reactance is zero.
Because it is. Capacitive reactance is a form of resistance, along with inductive reactance. All are measured in ohms.
Inductive reactance, as well as capacitive reactance, is measured in ohms.
Inductive reactance is traditionally positive while capacitive reactance is traditionally negative. Those are the conventions used by electrical engineers and they are consistent with a time-dependency of exp(+jwt).
Inductive reactance is traditionally positive while capacitive reactance is traditionally negative. Those are the conventions used by electrical engineers and they are consistent with a time-dependency of exp(+jwt).
yesAnswerNo, but you can counter its effects. For example, if your load is inductive, then you can counter the effects of its inductive reactance by introducing capacitors with equal capacitive reactance.