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Why is capacitive voltage higher than inductive voltage in an R-L-C circuit?
Wiki User
∙ 11y ago
It isn't necessarily so. The capacitive voltage is the product of the current and capacitive reactance, while the inductive voltage is the product of the current and the inductive reactance. So it depends whether the capacitive reactance is greater or smaller than the inductive reactance!
Wiki User
∙ 11y ago
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What happens in series resonance?
The properties of a series alternating-current L-R-C circuit at resonance are:the only opposition to current flow is resistance of the circuitthe current flowing through the circuit is maximumthe voltage across the resistive component of the circuit is equal to the supply voltagethe individual voltages across the inductive and capacitive components of the circuit are equal, but act in the opposite sense to each otherthe voltage appearing across both the inductive and capacitive components of the circuit is zeroif the resistance is low, then the individual voltages appearing across the inductive and capacitive components of the circuit may be significantly higher than the supply voltage
Why series resonance is called voltage resonance?
Series resonance isn't generally referred to as 'voltage resonance', but the expression probably comes from the fact that, at resonance, the voltage drop across the inductive component of a circuit is exactly equal to the voltage drop across the capacitive component of the circuit and, if the resistance of the resonant circuit is low in comparison with its reactance, then each of these voltage drops can be significantly higher than the supply voltage.
Is it possible to have a voltage drop across the energy storage element greater than the supply?
Yes. For a condition called 'series resonance', if the resistance of the circuit is low compared with the inductive reactance and capacitive reactance, then the voltage drop across the capacitor can be VERY much higher than the supply voltage.
What benefit is there for getting higher open circuit voltage?
There is no particular benefit for having a higher open-circuit (or 'no-load') voltage. In fact, an ideal voltage source would have no internal resistance and, therefore, its open-circuit voltage would be identical to its closed-circuit voltage.
Why in inductor the current lags the voltage?
Because in an AC circuit, a capacitor opposes the change of voltage in at. At the peak of the voltage waveform, there is no change (it is nearly flat), so at this same point in time, the current waveform is at zero. Likewise, when the voltage waveform crosses zero, it is changing at its fastest rate, so the current is at its peak. If you draw these two waveforms next to one another, you will see the voltage has the appearance of being behind the current - hence the term 'lag'.
What happens in series resonance?
The properties of a series alternating-current L-R-C circuit at resonance are:the only opposition to current flow is resistance of the circuitthe current flowing through the circuit is maximumthe voltage across the resistive component of the circuit is equal to the supply voltagethe individual voltages across the inductive and capacitive components of the circuit are equal, but act in the opposite sense to each otherthe voltage appearing across both the inductive and capacitive components of the circuit is zeroif the resistance is low, then the individual voltages appearing across the inductive and capacitive components of the circuit may be significantly higher than the supply voltage
Why series resonance is called voltage resonance?
Series resonance isn't generally referred to as 'voltage resonance', but the expression probably comes from the fact that, at resonance, the voltage drop across the inductive component of a circuit is exactly equal to the voltage drop across the capacitive component of the circuit and, if the resistance of the resonant circuit is low in comparison with its reactance, then each of these voltage drops can be significantly higher than the supply voltage.
When a circuit is inductive the current has what voltage?
This doesn't make sense, "current" is "amperage" so the higher the voltage the lower the amperage, and the lower the voltage the higher the amperage.
Is it possible to have a voltage drop across the energy storage element greater than the supply?
Yes. For a condition called 'series resonance', if the resistance of the circuit is low compared with the inductive reactance and capacitive reactance, then the voltage drop across the capacitor can be VERY much higher than the supply voltage.
What is buck boost converter?
Any device that outputs a voltage higher than its input voltage. This device can be capacitive, inductive, or other.
What benefit is there for getting higher open circuit voltage?
There is no particular benefit for having a higher open-circuit (or 'no-load') voltage. In fact, an ideal voltage source would have no internal resistance and, therefore, its open-circuit voltage would be identical to its closed-circuit voltage.
What is open circuit voltage in a Fuel Cell?
A: All batteries will eventually fail when that occurs the voltage out of then can be zero or higher voltage when new, In that case the battery has failed but if you measure the output it will have a higher voltage because there is no load or open circuit as soon as the load is applied the voltage just disappear this condition is called open circuit voltage
What is the higher voltage at the electrode before the arc is struck called what is it's advantages to welding?
Open circuit voltage is the voltage at the electrode before striking an arc (with no current being drawn). The higher the open circuit voltage, the easier it is to strike an arc because of the initial higher voltage pressure.
Is it possible to have a voltage drop across the energy storage element greater than the supply in series RLC circuit?
If, by 'storage element', you are are referring to the inductive and capacitive components (?), then the answer is yes. The voltage drop across these components is given by:VL = I XLVC = I XCIn fact, at resonance, if the resistance is low, then VLand VC can be very much higher than the supply voltage.
Why in inductor the current lags the voltage?
Because in an AC circuit, a capacitor opposes the change of voltage in at. At the peak of the voltage waveform, there is no change (it is nearly flat), so at this same point in time, the current waveform is at zero. Likewise, when the voltage waveform crosses zero, it is changing at its fastest rate, so the current is at its peak. If you draw these two waveforms next to one another, you will see the voltage has the appearance of being behind the current - hence the term 'lag'.
Is gold used in circuit breakers?
Certainly not in the case of high-voltage circuit breakers. Probably not in low-voltage circuit breakers, as copper is a better conductor and has a higher melting point.
High voltage will trip a circuit breaker?
A higher voltage means that a higher current will flow in the same load. It is the current that causes the breaker to trip.
