BY adding excess
Filter off excess MgCO3(s) .
heat the filter to get a saturated solution ,
cool to obtain crystals ,
filter .
H2SO4(aq)+MgCO3(s)--->MgSO4(aq)+H2CO3(g)
No reaction, because a metal will not displace itself.
( If this is true then why is there a reaction?) The magnesium strip corrodes, leaving a dark messy liquid.
No reaction would take place as Mg is higher than Fe in reactivity
Put Mg in CuSO4 solution and remove the brown ppt. to obtain the solution of MgSO4
Magnesium sulfate is not so soluble in water to prepare a 4 M solution.
This is the chemical formula of magnesium sulfate.
CuSO4 + MgCl2 -> CuCl2 + MgSO4
1 meter = 100 cm 4m 20cm = 4 x 100 + 20 cm = 420 cm
4m /s
By unit of length and distance and conversion ,we can say that 1 m=3.28 4 m =13.12 feet
First, you must find the acceleration. You can do so using the following kinematics equation: V=V0+at (V is the final velocity, Vo is the initial velocity, a is acceleration and t is time.) The object ends up stopping, so V = 0. V0 is given as 4 m/s and t is given as 10s. So: 0 = 4m/s + a(10s) -4m/s = a(10s) (-4m/s)/(10s) = a -0.4m/s2 = a Now you can use Newton's Second Law equation to find the force. F=ma (F is force, m is mass, and a is acceleration.) Mass is given as 80kg, and the acceleration has been calculated to be -0.4m/s2. F=(80kg)(-0.4m/s2) F= -32 N
There are no forces external to the engine and car involved here*, thus this is a case of conservation of momentum. Note, an unknown amount of energy is absorbed by the couplers and other parts of the engine and car, so the conservation of energy equation is not useful here. Momentum = velocity X mass Since momentum is conserved, the total velocity X mass before the collision will equal total velocity X mass after the collision. If we define the mass of the car as M, then the mass of the engine is 4M Let: the initial velocity of the engine = Ve1 = 10Kmh the initial velocity of the car = Vc1 = 0 Kmh the final velocity = V2 (it is the same for both the car and the engine) So the initial momentum is: (Ve1) (4M) + (Vc1) (M) = (10) (4M) + (0) (M) = 40M The final momentum is: (V2) (4M + M) = (V2) (5M) = 5V2M Setting the initial momentum equal to the final momentum gives: 40M = 5V2M Doing the algebra gives: 40 = 5V2 8 = V2 So, the answer is the final velocity is 8 Kmh *We are assuming friction of the wheels on the track is negligible and that the track is level so that gravity can be ignored.
It has no solution since subtracting 4m from both sides leads to -4 = 0 which is not true.
16
The answer is 0,08 mol.
You need 116,88 g dried and pure sodium chloride.
m = -19
4m
The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl
3.3912
4m
The area of 4m by 4m is 16 square meters.
4m = 13.12 feet
it can only remove by hardware solution. u can remove them 4m the board.