BY adding excess
Filter off excess MgCO3(s) .
heat the filter to get a saturated solution ,
cool to obtain crystals ,
filter .
H2SO4(aq)+MgCO3(s)--->MgSO4(aq)+H2CO3(g)
4m /s
By unit of length and distance and conversion ,we can say that 1 m=3.28 4 m =13.12 feet
First, you must find the acceleration. You can do so using the following kinematics equation: V=V0+at (V is the final velocity, Vo is the initial velocity, a is acceleration and t is time.) The object ends up stopping, so V = 0. V0 is given as 4 m/s and t is given as 10s. So: 0 = 4m/s + a(10s) -4m/s = a(10s) (-4m/s)/(10s) = a -0.4m/s2 = a Now you can use Newton's Second Law equation to find the force. F=ma (F is force, m is mass, and a is acceleration.) Mass is given as 80kg, and the acceleration has been calculated to be -0.4m/s2. F=(80kg)(-0.4m/s2) F= -32 N
To convert 4 meters and 62 centimeters to centimeters, first convert 4 meters to centimeters by multiplying 4 by 100 (since 1 meter is equal to 100 centimeters), which equals 400 centimeters. Then add the additional 62 centimeters to get the total length in centimeters. Therefore, 4 meters 62 centimeters is equal to 462 centimeters.
There are no forces external to the engine and car involved here*, thus this is a case of conservation of momentum. Note, an unknown amount of energy is absorbed by the couplers and other parts of the engine and car, so the conservation of energy equation is not useful here. Momentum = velocity X mass Since momentum is conserved, the total velocity X mass before the collision will equal total velocity X mass after the collision. If we define the mass of the car as M, then the mass of the engine is 4M Let: the initial velocity of the engine = Ve1 = 10Kmh the initial velocity of the car = Vc1 = 0 Kmh the final velocity = V2 (it is the same for both the car and the engine) So the initial momentum is: (Ve1) (4M) + (Vc1) (M) = (10) (4M) + (0) (M) = 40M The final momentum is: (V2) (4M + M) = (V2) (5M) = 5V2M Setting the initial momentum equal to the final momentum gives: 40M = 5V2M Doing the algebra gives: 40 = 5V2 8 = V2 So, the answer is the final velocity is 8 Kmh *We are assuming friction of the wheels on the track is negligible and that the track is level so that gravity can be ignored.
It has no solution since subtracting 4m from both sides leads to -4 = 0 which is not true.
16
By definition, 1 liter of a 4 M solution must contain 4 moles of the solute. Because solutions are homogeneous mixtures and 250 ml is one quarter of a liter, the amount of KCl required is 1 mole. The gram molar mass* of KCl is 74.55 grams; this is therefore the amount of KCl required.** __________________________________ *Because KCl is an ionic rather than a molecular compound, its "gram molar mass" should preferably be called its "gram formula unit mass". **Strictly according to the rules of significant digits, this answer should be written as "7 X 10" grams, because the datum "4M" needed to calculate the answer contains only one significant digit.
You need 116,88 g dried and pure sodium chloride.
m = -19
The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl
The pH of the solution can be calculated using the formula: pH = -log[H3O+]. Substituting the given value of [H3O+] = 2 x 10^-4M into the formula, pH = -log(2 x 10^-4) = 3.7. Therefore, the pH of the solution is 3.7.
4m
The area of 4m by 4m is 16 square meters.
4m = 13.12 feet
To determine how many liters of a 4M lithium bromide (LiBr) solution can be made from 100 grams of LiBr, we first need to calculate the number of moles in 100 grams. The molar mass of lithium bromide is approximately 86.84 g/mol, so 100 grams corresponds to about 1.15 moles. A 4M solution contains 4 moles of solute per liter, thus 1.15 moles can produce approximately 0.29 liters (1.15 moles ÷ 4 moles/L). Therefore, 100 grams of lithium bromide can make about 0.29 liters of a 4M solution.
it can only remove by hardware solution. u can remove them 4m the board.