smallest = min (one_number, another_number);
...or...
smallest = one_number < another_number ? one_number : another_number;
That A + B /c is A+B/c but you really need to know the answer
for the largest number: #include<stdio.h> void main() { int a,b,c,number,largestnumber; a=99; b=9; c=77; if(a>b) { number=a; } else if(b>c) { number=b; } else { number=c; } largestnumber=number; printf("%d",largestnumber); }
helicopter
Find the number of moles for both of them , so :-for F 259.2/19 =13.64210526for C 40.8/12 = 3.4then divide by the smallest number to find the smallest ratio, so divide by 3.4for F (259.2/19)/3.4 =4.0124for C 3.4/3.4 = 1so i think we have 4 of F and 1 of Cso i think : CF4
what is if(!(str[i]==32))
Write a C program called MonthDays to find the number of days in a given month Test your code with different input values to demonstrate that your function is robust?
You can have a function with no parameters.
int findSmallest(int *list, int listsize) { int i; int smallest = list[0]; for(i = 1; i < listsize; i++) { if(list[i] < smallest) smallest = list[i]; } return smallest; }
#include<stdio.h> #include<conio.h> void main() { int a,b,c; clrscr(); printf("Enter any three numbers"); scanf("%d%d%d",&a,&b,&c); if(a>b&&a>c) printf("A is greatest"); else if(b>a&&a>c) printf("B is greatest"); else if(c>a&&c>b) printf("C is greatest"); if(a<b&&a<c) printf("A is smallest"); else if(b<a&&b<c) printf("B is smallest"); else if(c<a&&c<b) printf("C is smallest"); getch(); }
There are many ways to find the chromatic number. One way is to write the chromatic polynomial and obtain it from that. For example, let's look at a complete graph on 3 points which looks like a triangle. We can color the first vertex in x ways, the second is x-1 ways and the third in x-2 ways. So the chromatic polynomial is C(x)=x(x-1)(x-2) not the smallest natural number, N, such that C(N) is not equal to zero is the chromatic number. So in this case it is 3. This number tells us the we can color the graph with 3 different colors and have no vertices with the same color. Any smaller number of colors, say 2 would not work.So the answer is find C(x) the chromatic polynomial and then find the smallest natural number such that C(x) is not zero. There are many other methods to find it, but that one is sometimes the simplest.
Your best bet would probably be to iterate through the array using a for loop and compare each value to the current low and high values (which you would store in a local variable) for example: for each element in array { if current is less than lowest_value lowest_value = current else if current is greater than highest_value highest_value = current }
It is a bar-code variant, code128c https://en.wikipedia.org/wiki/Code_128