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In a 24 bit subnet (subnet mask = 255.255.255.0), the address 192.1.6.255 is the broadcast address for the subnet 192.1.6.0/24.
Varies from machine to machine:many early machines had address busses only 12 to 18 bits wideearly microprocessors has address busses 10 to 14 bits wide16 bit address busses were common on microprocessors in the early 1980sthe 8086 had a 20 bit address bus and the 68000 a 24 bit address busmost modern computers have 32 bit address busses with high-end ones having as many as 64 bit address busses
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32 bit address line can access 4GB of memory. As 2^10 -> 1KB; 2^20 -> 2MB; 2^30 -> 1GB and so on.... 32 bit gives (2^30) * (2^2) = 1GB * 4 = 4GB;
An 80286 has a 24 bit address bus. As such, it can address 224, or 16,777,216, or 16 MB of memory.
Which processor has a 32-bit Data Bus and a 24-bit Address Bus?
A microprocessor that uses 24 bit addressing, such as the Intel 80286, can address 224 or 16,777,216 memory locations. The IBM MainFrame, 360/44 or any modern version running in AMODE=24 also has the same capacity.
for 16 MB memory has 24 address lines
16.7 million. 24 bit is also referred to "True Color".
31 bit addressing is a way of accessing the virtual memory. Based on the memory available the bit in the address can change. Or viceversa. for 31 bit the memory available is gb and for 24 bit its 16mb.
The memory address space is 64 MB, which means 226. However, each word is 4 bytes, which means that you have 224 words. This means you need log2 224 or 24 bits, to address each word.
The most common binary word length for audio is 16-bit. Bit depths of 20- and 24-bit resolution are also commonly used.