24
There are 4094 usable IP addresses in a 20-bit subnet.
In a 24 bit subnet (subnet mask = 255.255.255.0), the address 192.1.6.255 is the broadcast address for the subnet 192.1.6.0/24.
It depends on your subnet mask. IP addresses begining with 170 are Class-B networks and if your using classful network boundries, then the network would be 170.3.0.0. But, its unlikely you're using classful boundries these days. The most common subnet uses a 24-bit subnet mask (255.255.255.0). It that's the case, then the network would be 170.3.24.0 There are of course other possibilites- everything depends on the subnet mask.
By default Class C subnet mask is 255.255.255.0 = 24 bits for network id and 8 bits for host id. in Binary 1111 1111. 1111 1111. 1111 1111. 0000 0000 Here all 1s are Network bits and all 0s are host bits. For this subnet mask you can have 256 hosts. And you can use 254 host and asign IP address to them. By Saurabh
A Class C IP address has 24 bits for network and 8 bits for host. So to have a subnet mask of 26 bits, you will need to use 2 bits from host part.Number of subnets is given by the formula : 2^(no. of bits used from host part).Hence number of subnets in this case would be = 2^2 = 4.For e.g. if the class C IP address is 200.168.210.0the 4 subnet addresses would be :11001000.10101000.11010010.00000000 = 200.168.210.011001000.10101000.11010010.01000000 = 200.168.210.6411001000.10101000.11010010.10000000 = 200.168.210.12811001000.10101000.11010010.11000000 = 200.168.210.192Note: The digits in bold are the mask bits.
you can't. There's no way to know from an IP address wha the subnet mask is. However, there are some likely guesses. Since 195.0.8.0 ends with a zero, the subnet is probably a 24-bit mask: 255.255.255.0 But it doesnt have to be. The network administrator knows for sure. fm
The subnet mask - expressed in binary - starts with a number of ones, followed by zeros. If (for example) the subnet mask is 255.255.255.0, this can also be written as /24 - that means that the first 24 bits are ones. In this example, that means that the first 24 bits of the IP address (in this case, exactly 3 bytes) are shared by all devices in the same subnet. So, if your IP address is 200.3.85.7, and the subnet mask is 255.255.255.0, all other computers in the same subnet will also start with 200.3.85.
/24
The subnet mask would be 255.255.255.0
When we express an IPv4 network address, we add a prefix length to the network address. The prefix length is the number of bits in the address that gives us the network portion. For example, in 172.16.4.0 /24, the /24 is the prefix length - it tells us that the first 24 bits are the network address. This leaves the remaining 8 bits, the last octet, as the host portion.
I guess the network address is 192.168.1.0/24. This can be subnetted if we take two bits from host part to network part. 192.168.1.0/24 in binaries... 11000000.10101000.00000001.00000000 - IP Address 11111111.11111111.11111111.00000000 - Subnet Mask Take two bits from host part to network part 11000000.10101000.00000001.00 000000 - IP Address 11111111.11111111.11111111.11 000000 - Subnet Mask Now we get four networks... 1) 11000000.10101000.00000001.00 000000 - IP Address 11111111.11111111.11111111.11 000000 - Subnet Mask 192.168.1.0 - IP Address 255.255.255.192 - Subnet Mask 2) 11000000.10101000.00000001.01 000000 - IP Address 11111111.11111111.11111111.11 000000 - Subnet Mask 192.168.1.64 - IP Address 255.255.255.192 - Subnet Mask 3) 11000000.10101000.00000001.10 000000 - IP Address 11111111.11111111.11111111.11 000000 - Subnet Mask 192.168.1.128 - IP Address 255.255.255.192 - Subnet Mask 4) 11000000.10101000.00000001.11 000000 - IP Address 11111111.11111111.11111111.11 000000 - Subnet Mask 192.168.1.192 - IP Address 255.255.255.192 - Subnet Mask We get four networks and the networks are 1) 192.168.1.0/26 2) 192.168.1.64/26 3) 192.168.1.128/26 4) 192.168.1.192/26 Refer: http://www.omnisecu.com/tcpip/internet-layer-ip-subnetting-part1.htm
254 host as 172.16.32.0/24