truzi i Ghal
Ah, honey, in C, you can get the number of elements in an array by dividing the total size of the array by the size of one element. So, if you have an array of integers, you can do something like int size = sizeof(array) / sizeof(array[0]); and voilà, you've got the number of elements. Just be careful with those pesky pointers and make sure you're not trying to count elements in a pointer instead of an actual array.
Using the function "count". <?php $foo = array("John", "Jacob", "Jingleheimer", "Schmidt"); echo count($foo); // <-- outputs the number 4 ?>
#include<stdio.h> #include<conio.h> int main(void) { int a[10],i;//array declaration clrscr(); printf("\n enter the elements of array"); for(i=0;i<10;i++) scanf("%d",&a[i]); printf("\n the elements you enter into the array"); for(i=0;i<10;i++) printf("%5d",a[i]); getch(); return 0; }
/* PROGRAM TO SORT ARRAY ELEMENTS USING BUBBLE SORT*/ #include #include void main() { int i,j,n,t,a[50]; clrscr(); printf("ENTER THE ARRAY SIZE:\n"); scanf("%d",&n); printf("ENTER THE ARRAY ELEMENTS:\n"); for(i=0;i
If all elements of the array are in use then the last record is referred to as MAX-1. If you are using a count variable to remember how far into the array you are using then this variable will keep track of the last allocated value in the array.
Set sum = 0, then add each of the elements of the array, one by one. Use a for loop to process each element of the array.Set sum = 0, then add each of the elements of the array, one by one. Use a for loop to process each element of the array.Set sum = 0, then add each of the elements of the array, one by one. Use a for loop to process each element of the array.Set sum = 0, then add each of the elements of the array, one by one. Use a for loop to process each element of the array.
To detect the duplicate, you will have to write a nested loop that compares each element with all the previous elements.To actually delete the duplicate, once you find it, you have to move over all the elements after the duplicate. If the order of the elements doesn't matter, it is faster to just move the LAST array element, overwriting the duplicate element. Use a variable to keep track how many elements of the array are "usable". For example, if your array had 10 elements, and you delete 1, the array size will still be 10... but (after moving the elements over) only 9 of those elements have useful information.
int main() { int array[3][3]; int i; for(i=0; i <9;i++) { printf("the element is %d\n", array[i/3][i%3]); } return 0; }
Yes. The array name is a reference to the array, so you can use sizeof (name) / sizeof (name[0]) to determine the number of elements. Note that sizeof (name) alone gives the length of the array in bytes.
I guess you mean operation top: return the topmost element without deleting it from the stack.int top (const struct stack *from, stacktype *into){if (from->elements==0) return -1; /* EMPTY */*into = from->array[from->elements -1];return 0; /* OK */}compare with pop:int pop (struct stack *from, stacktype *into){if (from->elements==0) return -1; /* EMPTY */*into = from->array[from->elements -1];--from->elements;return 0; /* OK */}
The number of dimensions is immaterial. All arrays are implemented as a one dimensional array. A multidimensional array is simply an array where every element is itself an array. The only thing actually known about any array is that its name is a reference to the start address. Unlike an ordinary (non-array) variable, the elements in the array do not have names, we can only refer to them by their memory offsets from the start of the array. As such, in order to obtain the values stored at those offsets, we must dereference them. While the subscript operator gives us notational convenience, it's easy to forget that there's actually pointer arithmetic and dereferencing going on behind the scenes.
It has 170 diagonals by using the diagonal formula