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Set sum = 0, then add each of the elements of the array, one by one. Use a for loop to process each element of the array.
Set sum = 0, then add each of the elements of the array, one by one. Use a for loop to process each element of the array.
Set sum = 0, then add each of the elements of the array, one by one. Use a for loop to process each element of the array.
Set sum = 0, then add each of the elements of the array, one by one. Use a for loop to process each element of the array.
What else can I help you with?
How do you write an assembly language program to find the sum of n numbers using array?
write an assembly language program to find sum of N numbers
What is the minimum unique array sum that can be achieved?
The minimum unique array sum that can be achieved is when all elements in the array are different, resulting in the sum of the array being equal to the sum of the first n natural numbers, which is n(n1)/2.
C program to find sum of n numbers using functions over loading?
C does not support function overloading. Every function in the global namespace must have a unique name. However, to find the sum of n numbers, place the numbers in an array of appropriate size and pass the array to the following function: // Sum an array of n values int sum (int values[], unsigned n) { int result = 0; for (int i=0; i<size; ++i) result += values[i]; return result; }
Write a program to calculate the sum of n numbers using array?
int myArray[N]; //where N is a constant int mySum = 0; ... for (int arrayIndex1 = 0; arrayIndex1 < N; arrayIndex1++) { cin >> myArray[arrayIndex1]; } ... for (int int arrayIndex2 = 0; arrayIndex2 < N; arrayIndex2++) { mySum +=myArray[arrayIndex2]; } ...
Program to find sum of n numbers using recursion function?
int sum(n) { if (n==0) return 0; else return n+sum(n-1); }
Program in c to get the sum of n numbers present in an array using one dimensional array?
#include<stdio.h> #include<conio.h> main() { int num, n,sum=0,i=0; printf("enter the number of elements to be added "); scanf("%d",&n); printf("enter %d numbers",n); while(i<n) { scanf("%d",&num); sum=sum+num; i=i+1; } printf("the sum of %d numbers is %d",n,sum); getch(); }
C program to find sum of n number using for loop?
#include<stdio.h> void main() { long long int sum=0,n,i,b; printf("How many numbers do you want to add?\n"); scanf("%lld",&n); printf("Enter those %lld numbers\n",n); for(i=0;i<n;i++) { scanf("%lld",&b); sum=sum+b; } printf("Sum of all the numbers you entered is %lld",sum); getch(); }
How do you get the sum of consecutive cubed numbers?
The sum of the first n cubed numbers is: [n*(n+1)/2]2 which is the same as the square of the sum of the first n numbers.
Write a program to add array of N elements?
int sumArray(int N, int* A) { int sum = 0; do sum += A[N-1] while (N-- > 1); return sum; }
How do you find the average of n numbers?
The average of n numbers = (sum of n numbers) / (count of n numbers).
Java-find average using array?
public static final double getAverage(final int[] ns) { if (ns.length == 0) { return 0.0; } int sum = 0; for (int n : ns) { sum += n; } return ((double) sum) / ns.length; }
What is the c plus plus program for printing sum to n natural numbers?
main() { int i, n, sum=0; cout<<"Enter the limit"; cin>>n; for(i=0;i<=n;i++) sum=sum+i; cout<<"sum of "<<n<<" natural numbers ="<<sum; getch(); }
