There should be Silver nitrate dissolved in the water, only then it can react
Silver iodide (AgI), a precipitate insoluble in water, don't react with potassium nitrate.
When potassium iodide and lead nitrate react, lead iodide precipitate forms due to the low solubility of lead iodide in water. This reaction is a double displacement reaction where the potassium and lead ions switch partners, resulting in the formation of the insoluble lead iodide.
Silver nitrate solution and potassium iodide solution can be mixed to form silver iodide due to a double displacement reaction where the silver ions from silver nitrate react with the iodide ions from potassium iodide to form insoluble silver iodide precipitate. The balanced chemical equation for this reaction is: AgNO3 (aq) + KI (aq) → AgI (s) + KNO3 (aq).
They form Silver Iodide and Poassium nitrate. Silver Iodide is a yellow coloured compound which forms precipitate in the solution. Potassium Nitrate remains dissolved. These reactions only take place in solution. When both reactants are in solid state then reaction may not occur, or it is too slow to be observed.
When silver nitrate and strontium iodide react, a double displacement reaction occurs. Silver iodide and strontium nitrate are formed as products. Silver iodide is a yellow precipitate while strontium nitrate remains in solution.
A white precipitate forms when silver nitrate and potassium carbonate react, due to the formation of insoluble silver carbonate.
When potassium iodide reacts with lead nitrate, a double displacement reaction occurs. The potassium ion and the lead ion switch places to form potassium nitrate and lead iodide. This reaction results in the formation of a yellow precipitate of lead iodide.
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.
The precipitate formed from the reaction between silver nitrate and potassium chloride is white in color. This precipitate is silver chloride, which is insoluble in water and forms when the silver ions from silver nitrate react with chloride ions from potassium chloride.
The net ionic equation for the reaction between sodium iodide (NaI) and silver nitrate (AgNO3) when a precipitate is formed is: 2Ag+ + 2I- -> Ag2I (s) This equation represents the formation of silver iodide (AgI) precipitate when silver cations react with iodide anions.
When potassium and iodine react, they form potassium iodide. The ions involved are K+ (potassium ion) and I- (iodide ion).
No, they do not