G would remain the same, it's the gravitational constant which is the same everywhere in the universe.
g would increase by 4 times, assuming that the radius of the earth didn't increase.
i think value of g becomes zero
The question cannot be answered because the question provides no information on the mass of the "new" earth. Also, if it is a more massive earth then it is more likely to have a denser atmosphere.
representative currency
g is directly proptional to mass of earth. if the mass of eath will be increase mass of g will be also increase.If the mass of earth will be decrease the mass of g will bi also decrease.If the mass of earth will increase four times then the mass of g will be also increase four times. G is a gravitational contant.it remain same throughout the universe if the mass of earth will become four times,the value of G will not change it will remain the same as it is a constant.its value is 6.67x 10^-11 N-M^/KG
Earth's gravity .It's value is 9.8ms-2
If the mass of an object were to increase then the GPE ( gravitational potential energy) of that object will increase i.e. the pulling power of the object will increase (the value of g will increase). Hope this helps
i think value of g becomes zero
9.8 m/s2 ---------------------- Yes this is the average value of acceleration due to gravity near by the surface of the earth. As we go higher and higher level this g value decreases and becomes almost negligible. Same way as we go deeper and deeper the g value decreases and at the centre of the earth its value becomes zero.
739 times
It becomes ten times as large.
At the surface, it is 2.64 times its value at the Earth's surface.
274 meters per second squared. That's about 28 times Earth gravity.
The acceleration of gravity at the 'surface' of Jupiter is 2.639 times its value at the Earth's surface.
inflation happens when money loses its value and it affected the Roman Empire.
The Value of the Determinant becomes 0
1/9th of its present value
The time period of a pendulum would increases it the pendulum were on the moon instead of the earth. The period of a simple pendulum is equal to 2*pi*√(L/g), where g is acceleration due to gravity. As gravity decreases, g decreases. Since the value of g would be smaller on the moon, the period of the pendulum would increase. The value of g on Earth is 9.8 m/s2, whereas the value of g on the moon is 1.624 m/s2. This makes the period of a pendulum on the moon about 2.47 times longer than the period would be on Earth.