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How would the time period of a simple pendulum clock be affected if it were on the moon instead of the earth?
Wiki User
∙ 11y ago
The time period of a pendulum would increases it the pendulum were on the moon instead of the earth.
The period of a simple pendulum is equal to 2*pi*√(L/g), where g is acceleration due to gravity. As gravity decreases, g decreases. Since the value of g would be smaller on the moon, the period of the pendulum would increase. The value of g on Earth is 9.8 m/s2, whereas the value of g on the moon is 1.624 m/s2. This makes the period of a pendulum on the moon about 2.47 times longer than the period would be on Earth.
Wiki User
∙ 11y ago
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What will be the effect of time period of a simple pendulum if its mass is doubled and its amplitude is halved?
The PERIOD of a Simple Pendulum is affected by its LENGTH, and NOT by its Mass or the amplitude of its swing. So, in your case, the Period of the Pendulum's swing would remain UNCHANGED!
What happens to time period of a simple pendulum if a heavy body is attached to it instead of bob?
The period of a simple pendulum is independent of the mass of the bob. Keep in mind that the size of the bob does affect the length of the pendulum.
What factors affect the period of a pendulum?
In a simple pendulum, with its entire mass concentrated at the end of a string, the period depends on the distance of the mass from the pivot point. A physical pendulum's period is affected by the distance of the centre-of-gravity of the pendulum arm to the pivot point, its mass and its moment of inertia about the pivot point. In real life the pendulum period can also be affected by air resistance, temperature changes etc.
Why a compound pendulum is called equivalent simple pendulum?
Compound pendulum is a physical pendulum whereas a simple pendulum is ideal pendulum. The difference is that in simple pendulum centre of mass and centre of oscillation are at the same distance.
How do the parameters of a simple pendulum affect the period of a pendulum?
The period increases as the square root of the length.
What will happen to length of a simple pendulum if its time period is doubled?
time period of simple pendulum is dirctly proportional to sqare root of length...
What would be the period of a pendulum with the length of 10 meters?
For a simple pendulum: Period = 6.3437 (rounded) seconds
What happens to the period of a simple pendulum if the pendulum length is doubled?
The period increases - by a factor of sqrt(2).
In simple pendulum if string is flexible then what is effect on time period?
multiply the length of the pendulum by 4, the period doubles. the period is proportional to the square of the pendulum length.
How does the period of a pendulum difference theoretically with length for simple pendulum?
The period is directly proportional to the square root of the length.
Does amplitude effect the period of a pendulum?
no it doesnt affect the period of pendulum. the formulea that we know for simple pendulum is T = 2pie root (L/g)
What are conditions used while calculating time period of simple pendulum?
The time period of a simple pendulum is calculated using the following conditions: Length of the pendulum: The longer the length of the pendulum, the longer it takes for one complete back-and-forth swing. Acceleration due to gravity: The time period is inversely proportional to the square root of the acceleration due to gravity. Higher gravity results in a shorter time period. Angle of displacement: The time period is slightly affected by the initial angle of displacement, but this effect becomes negligible for small angles.
