4a2+ 25 does not factor over the real number field. In the complex numbers , it
factors as (2a +5i)(2a - 5i).
This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
(2a = 5i)(2a - 5i) where i is the square root of -1
4x2+20x+25 (2x+5)^2
362+60x+25 (6x+5)(6x+5)
(x-5i)(x+5i)
(6x + 5)(6x + 5) or (6x + 5)2
25 is not a multiple of 10, so the greatest common factor would not be 10. A lower common factor would be 5, because 10, 20 and 25 all divide by 5, so 5 is the greatest common factor of 10, 20 and 25.
(2a + 5)(2a - 5)
x2 + 10y + 25 doesn't factor neatly. If that was x2 + 10x + 25, it would factor to (x + 5)(x + 5) or (X + 5)2
4n-20n+25
4x2+20x+25 (2x+5)^2
362+60x+25 (6x+5)(6x+5)
5(2r + 5)
4x+516x2 + 40x + 25= (4x + 5) (4x + 5)
(4x + 5)(4x + 5)
Factor the polynomial x2 - 10x + 25. Enter each factor as a polynomial in descending order.
(2x - 5)(2x - 5)
(x-5i)(x+5i)
(x - 4)(x - 25)