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How would you precisely work out in two different ways the sum of 1499 plus 19 plus 99 using only Roman numerals throughout both calculations giving reasons why?
Wiki User
∙ 11y ago
With great difficulty because in accordance with the rules and regulations governing todays Roman numeral system that were introduced during the Middle Ages nowadays we would convert 1499, 19 and 99 into Roman numerals as MCDXCIX, XIX and XCIX respectively which makes arithmetical operations with them quite difficult if not impossible at all.
But notwithstanding todays configuration of Roman numerals inasmuch that there is evidence to suggest that the ancient Romans would have probably calculated the equivalent of these numbers in either of the folllowing formats:-
IMD+IXX = MDXVIII => (1500-1)+(20-1) = 1518
MDXVIII+IC = MDCXVII => 1518+(100-1) = 1617
Alternatively:-
MCCCCLXXXXVIIII+XVIIII = MDXVIII => 1499+19 = 1518
MDXVIII+LXXXXVIIII = MDCXVII => 1518+99 = 1617
Remember: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=M
Roman numerals: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1
Note that if we added I to MCCCCLXXXXVIIII it would then become MD so in order for it to retain its original value we must subtract I from MD therefore it follows that:-
MCCCCLXXXXVIIII = IMD = 1499
QED
Wiki User
∙ 11y ago
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