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How would you work out 19 plus 9 in four different ways and 19 minus 9 in four different ways but calculating all eight calculations completely in Roman numerals from start to finish with explanations?
Wiki User
∙ 9y ago
Since you ask how I would do it: I would forget about doing this in Roman; rather, I would convert everything to arabic numbers, which are much more appropriate for such calculations.
Wiki User
∙ 9y ago
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How would you calculate 9.5 plus 8.5 in two different ways and 9.5 minus 8.5 in two different ways but calculating all four calculations completely in Roman numerals with explanations?
The equivalent of 0.5 or 1/2 as a Roman numeral is S and so therefore the required calculations are as follows:-SX+SIX = XVIII => (10-0.5)+(10-1.5)= 18VIIIIS+VIIIS = XVIII => 9.5+8.5 = 18SX-SIX = I => (10-0.5)-(10-1.5) = 1VIIIIS-VIIIS = I => 9.5-8.5 = 1Note that in mathematics -(10-1.5) changes to 1.5-10QED
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What is the formula you use to calculate drug calculations?
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How would you actually add together 1666 and 1999 in two different ways entirely in Roman numerals throughout both calculations with explanations?
See answer to question: ' How do you add together 1666 and 1999 in two different ways using Roman numerals'
4 several different explanations theories of ruling-class unity?
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What is 1776 plus 249 added in two different ways and 1776 minus 249 subtracted in two different ways but working out all four calculations entirely in Roman numerals with explanations?
Under today's modern rules now governing the Roman numeral system the equivalent of 249 when converted into Roman numerals is now considered to be CCXLIX which does not lend itself quite easily to arithmetical operations but there exist credible evidence to suggest that the ancient Romans would have carried out the requested calculations as follows:-MDCCLXXVI+ICCL = MMXXV => 1776+(250-1) = 2025MDCCLXXVI+CCXXXXVIIII = MMXXV => 1776+249 = 2025MDCCLXXVI-ICCL = MDXXVII => 1776-(250-1) = 1527MDCCLXXVI-CCXXXXVIIII = MDXXVII => 1776-249 = 1527Note that in mathematics -(250-1) becomes -250+1 or as 1-250The above calculations were fairly simple and straight forward to work out but for more complicated calculations the Romans would make use of an abacus calculating device.QED
How would you calculate 19 plus 9 in two different ways and 19 minus 9 in two different ways but working out all four calculations entirly in Roman numerals with explanations?
The modern way of expressing 19 in Roman numerals is now XIX but the ancient Romans would have expressed it as IXX or as XVIIII because their equivalent Latin words are 'undeviginti' and 'novemdecim' respectively but there is no Latin equivalent for XIX and thus it logically follows that:-IXX+IX = XXVIII => (20-1)+(10-1) = 28XVIIII+VIIII = XXVIII => 19+9 = 28IXX-IX = X => (20-1)-(10-1) = 10XVIIII-VIIII = X => 19-9 = 10Remember that in mathematics --I = +I and that the above calculations can be considered to be mental arithmetic but for more serious calculations the Romans would have used an abacus calculating device.QED
What is 1776 plus 89.5 added in two different ways and 1776 minus 89.5 subtracted in two different ways entirely in Roman numerals with explanations?
The rules now governing the Roman numeral system as we know them today had nothing to do with the Romans because they were introduced during the Middle ages but there exist credible evidence to show that the ancient Romans would have worked out all four calculations in the following formats:-MDCCLXXVI+SXC = MDCCCLXVS => 1776+(100-10.5) = 1865.5MDCCLXXVI+LXXXVIIIIS = MDCCCLXVS => 1776+89.5 = 1865.5MDCCLXXVI-SXC = MDCLXXXVIS => 1776-(100-10.5) = 1686.5MDCCLXXVI-LXXXVIIIIS = MDCLXXXVIS => 1776-89.5 = 1686.5Note that in mathematics -(100-10.5) becomes 10.5-100 and that the above calculations were fairly simple and straightforward to work out but for more complicated calculations the Romans would have used an abacus calculating device.QED
What is 1218 plus 558 added in two different ways and 1218 minus 558 subtracted in two different ways but working out all four calculations entirely in Roman numerals with explanations?
The following answers are self explanatory:-IIMCCXX+IIDLX = MDCCLXXVI => (1220-2)+(560-2) = 1776MCCXVIII+DLVIII = MDCCLXXVI => 1218+558 = 1776IIMCCXX-IIDLX = DCLX => (1220-2)-(560-2) = 660MCCXVIII-DLVIII = DCLX => 1218-558 = 660Note that the rules as we now know them today governing the Roman numeral system had little or nothing to do with the ancient Romans whatsoever because they were introduced during the Middle Ages and so therefore the Romans would have probably worked out the given simple calculations as shown above but for more complicated calculations the Romans would have made usage of an abacus calculating device.QED
How would you evaluate 49 plus 19 in two different ways and 49 minus 19 in two different ways showing all four calculations entirely in Roman numerals with explanations?
In today's modern conversion of Roman numerals 49 and 19 are now considered to be XLIX and XIX respectively but the ancient Romans would have probably worked out the above as follows:- IL+IXX = LXVIII => (50-1)+(20-1) = 68 XXXXVIIII+XVIIII = LXVIII => 49+19 = 68 IL-IXX = XXX => (50-1)-(20-1) = 30 XXXXVIIII-XVIIII => 49-19 = 30 For more complicated calculations the Romans would use an abacus calculating device.
How would you work out 1776 plus 549 in two different ways and 1776 minus 549 in two different ways but working out all four calculations entirely in Roman numerals with explanations?
Roman numerals are entirely inappropriate for doing such calculations. I believe the people in Roman times did such calculations on an abacus or something similar - which is basically similar to converting them to the Arabic numbers we use. If you really want to do it in Roman numerals - which is basically NOT a good idea - you would have to keep the thousands, hundreds, etc. separate, and handle carry (for addition) and borrowing (for subtraction).
What is 1999 plus 1776 added in two different ways and 1999 minus 1776 subtracted in two different ways but working out all four calculations in Roman numerals with explanations?
The rules as we know them today now governing the Roman numerals system had absolutely nothing to do with the Romans because they were introduced during the Middle Ages and as a result of these rules 1999 when converted into Roman numerals is now considered to be MCMXCIX which hardly lends itself quite easily for the purpose of arithmetical operations but notwithstanding the aforementioned inasmuch that there exist credible evidence to support the premiss that the ancient Romans would have worked out the requested calculations as in the following formats:-MDCCCCLXXXXVIIII+MDCCLXXVI = MMMDCCLXXV => 1999+1776 = 3775IMM+MDCCLXXVI = MMMDCCLXXV => (2000-1)+1776 = 3775MDCCCCLXXXXVIIII-MDCCLXXVI = CCXXIII => 1999 -1776 = 223IMM-MDCCLXXVI is the same as the above because IMM = MDCCCCLXXXXVIIIIThe above calculations were fairly simple and straightforward to work out but for more complicated calculations the Romans would have made use of an abacus calculating device.QED
