How would you write a program that counts the number of vowels in a string in assembly language?

Answer 1

int countVowels(const char* str) {

int i = 0;

int numVowels = 0;

while(str[i] != '\0') {

switch(str[i]) {

case 'a':

case 'e':

case 'i':

case 'o':

case 'u':

++numVowels;

}

++i;

}

return numVowels;

}

static int countVowels(String str) {

int numVowels = 0;

foreach(char ch in str) {

switch (ch) {

case 'a':

case 'e':

case 'i':

case 'o':

case 'u':

++numVowels;

break;

}

}

return numVowels;

}

Answer 2

Set a counter variable to zero

Loop through the string one character at a time until the end

Check if the letter is "A" If it is, increment a counter and skip to NextLoop.

Check if the letter is "E" If it is, increment a counter and skip to NextLoop.

Check if the letter is "I" If it is, increment a counter and skip to NextLoop.

Check if the letter is "O" If it is, increment a counter and skip to NextLoop.

Check if the letter is "U" If it is, increment a counter

Label: NextLoop (skip to here)

end of the loop

display the counter