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quantity of cement for M20 in one cubic meter
cement=1440 kg/m3
sand=1700 kg/m3
aggregate= 1600 kg/m3
Lets solve for M20 i.e, 1:1.5:3
1 bag of cement = 50 kg =34.7 litres
=35 litres
i.e, 0.035 m3
(item) (w/c ratio)(water) (cement)(sand)(aggregate)
volume(0.42)(21ltr)(0.035)(0.0525)(0.105)
voids - (0) (0) (0 60%) (40%) (45%)
solidvolume (-) (0.021) (0.014) (0.0315) (0.05775) *sum=0.124
Thus 50 kg of cement gives 0.124 m3 of concrete for M20 at 0.42 w/c ratio.
Hence,
cement required =0.035/0.124 =0.28 m3 i.e, 0.28*1440=403kg
sand required= 0.0525/0.124 =0.42 m3 i.e, 0.42*1700 = 714 kg
similarly aggregate required = 1360 kg
water required = 169 litre
Check: 403+714+1360 = 2477 i.e, density of concrete =2477kg/m3
*NOTE: The quantity of cement, sand, aggregate & water varies with the w/c ratio and the density of materials.
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