You son't even have to know the mass. If the speed is constant, there is no
acceleration. Because F=ma and 'a' is now 0, net force is now 0. Because this
is net force, it simply means that the forces acting on the object add up to
zero, and have the same effect as no force at all. It's always important to
know that f=ma only works on net force, so understanding what it actually
means is vital.
If the speed is constant, then the group of forces acting on the object is balanced. So the portion of the force acting in the direction of the motion must be equal and opposite to the force of friction.
You don't have enough information in this case. Kinetic energy depends on mass and speed. Speed can be calculated as distance / time - and no time is given, nor is there any other information that allows you to calculate the time. Note that even if time is given, you can calculate the average (mean) speed, but that will only give you a rough idea of the mean kinetic energy. In this problem, if the speed changes a lot, the average kinetic energy (averaged over time) will be greater than in the case of a constant speed. This is because kinetic energy is proportional to the square of the speed.
(acceleration X time) + beginning velocity = final speed
You can use Plank's relation to calculate the energy of the absorbed photon.E = h.f = h.c/LgivenE = Energy of a photon in Joulesf = frequency of the photon in s-1c = speed of light in m/sL = wavelength of the photon in metreh = Planck constant = 6.62606957×10−34 J.s
Find out the time using speed and acceleration, (time=speed/acceleration) and then use it to find out uniform velocity. From that find out uniform acceleration. (as uniform acceleration is equal changes of velocity over equal intervals of time)
If the speed is constant, then the group of forces acting on the object is balanced. So the portion of the force acting in the direction of the motion must be equal and opposite to the force of friction.
You cannot. Force is mass times acceleration. You have neither.
force=mass x acceleration. you have force lets say 100N. you are given a velocity of lets say 10m/s at the first second. and you are given speed. if you are given one speed, then you are given the change in velocity (your acceleration). if you are given multiple speeds, then you can figure out your change in velocity of the amount of time the speeds are given as (also your acceleration). So lets say you are given a speed of 30m/s at the third second (second second sounds redundant). Assuming acceleration is constant as always, 30-10=20m/s over 2 seconds. So 20/2=10m/s2. now you have force and acceleration. 100= m x 10m/s2. m=10kg.
You didn't specify what data is given. In general, for constant speed, the following formula is important (just use the definition of speed): speed = distance / time; or distance = speed x time. If distance is in km and time in hours, speed will be in km/hour; if distance is in meters and time in seconds, speed will be in meters/second.
If you know that the speed is constant, just divide the distance by the time it takes to travel that distance.
Measure the force (f) required to compress the spring a given amount (x) then use hooke's law to compute the spring constant (k) (f=kx)
Not enough information. If you also know an object's mass, you can use Newton's Second Law to find the acceleration. Then simply multiply acceleration x time to get the speed (assuming that the initial speed is zero).
its really easy
find the constant of variation and the slope of the given line from the graph of y=2.5x
Given mass and force, assuming the force acts continuously on the object throughout the movement and doesn't change direction, you can easily calculate acceleration experienced by body. a = F / m, where a is acceleration, F is force, m is mass. You can then use simple formula for distance traveled by body with some initial speed and under constant acceleration: S = v0t + at2 / 2 Formula comes from integrating linearly increasing speed over time.
T=RC T=Time Constant R=Resistance in ohms C= Capacitance in Farads
acceleration times speed