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b. Fe3 plus ions
When 90.0mL of 0.10M Fe3 plus 3 is added to 10.0 mL of SCN minus 1, you get an equilibrium molar concentration of FeNCS plus 2. This is determined from a calibration curve of 1.0x10-6 mol/L.
The answer is 3. Fe -> Fe3+ + 3e
Brownish green
Fe3 + I = FeI3
FeCl3
b. Fe3 plus ions
When 90.0mL of 0.10M Fe3 plus 3 is added to 10.0 mL of SCN minus 1, you get an equilibrium molar concentration of FeNCS plus 2. This is determined from a calibration curve of 1.0x10-6 mol/L.
Hg will have 80 electrons.
FeBr2 + H3PO4 <--> Fe3(PO4)2 + HBr
FeSO4 + K3PO4 ---> Fe3(PO4)2 + K2SO4
ferrous ions and Fe3+ is ferric ion
The answer is 3. Fe -> Fe3+ + 3e
An example is the ferric ion: Fe(III) or Fe3+.
Zn2 + Fe3NO3 -> Zn3NO2 + Fe3
Zn(s) → Zn2+(aq) + 2e- and Fe3+(aq) + e- → Fe2+(aq)
it should lose 3 electrons