FeBr2 + H3PO4 <--> Fe3(PO4)2 + HBr
In H2O the conjugate base is H2PO4-, being conjugated to the acid H3PO4. As well: H3PO4 is conjugated acid to the base H2PO4-.
K3PO4 + 3HCl -> 3KCl + H3PO4 Since K on the reactant side has 3 potassium atoms, K on the product side should also have 3 potassium atoms to balance the equation. Since you put the 3 on KCl of the product side, another 3 has to go on the Cl on the reactant side which also matches the 3 hydrogen atoms on the product side in H3PO4. If you check, the equation is now balanced. Everything that appears on the left, equally appears on the right
Fe + 2HBr = H2 + FeBr2 Iron plus hydrobromic acid equals hydrogen gas plus iron (II) bromide
Ferrous bromide is FeBr3 Do NOT confuse with Ferric bromide which is FeBr3
The reaction between H3PO4 (phosphoric acid) and NaOH (sodium hydroxide) can be represented by the following equation: H3PO4 + 3NaOH → Na3PO4 + 3H2O. Here, one molecule of phosphoric acid reacts with three molecules of sodium hydroxide to produce one molecule of sodium phosphate and three molecules of water.
The product of phosphoric acid (H3PO4) plus potassium hydroxide (KOH) reaction is potassium phosphate (K3PO4) and water (H2O).
Balanced equation:12 HClO4 + P4O10 = 4 H3PO4 + 6 Cl2O7
In H2O the conjugate base is H2PO4-, being conjugated to the acid H3PO4. As well: H3PO4 is conjugated acid to the base H2PO4-.
Your reaction is this...H3PO4 + 3KOH --> K3PO4 + 3H2OThis type of reaction is called a double replacement.Note: You didn't put a 4 on the oxygen on the phosphate group on the product side in your question. If it wasnt there the equation would not have been balanced so i put it in myself.
K3PO4 + 3HCl -> 3KCl + H3PO4 Since K on the reactant side has 3 potassium atoms, K on the product side should also have 3 potassium atoms to balance the equation. Since you put the 3 on KCl of the product side, another 3 has to go on the Cl on the reactant side which also matches the 3 hydrogen atoms on the product side in H3PO4. If you check, the equation is now balanced. Everything that appears on the left, equally appears on the right
The formula for iron(II) bromide is FeBr2.
Fe + 2HBr = H2 + FeBr2 Iron plus hydrobromic acid equals hydrogen gas plus iron (II) bromide
To solve this problem, you will need to use the balanced chemical equation provided to determine the mole ratios between the reactants and products. First, convert the volume of H3PO4 to liters by dividing by 1000 mL/L: 750 mL H3PO4 / 1000 mL/L = 0.750 L H3PO4 Next, convert the concentration of H3PO4 to moles/L: 6.00 M H3PO4 = 6.00 mol/L H3PO4 Now, use the volume and concentration to calculate the number of moles of H3PO4: 0.750 L H3PO4 * 6.00 mol/L H3PO4 = 4.50 mol H3PO4 Since the chemical equation shows a 1:1 mole ratio between H3PO4 and Ca(OH)2, there must be 4.50 mol Ca(OH)2 as well. To determine the mass of each product, you will need to know the molar masses of each compound. The molar mass of H3PO4 is 98.00 g/mol, and the molar mass of Ca(PO4)2 is 212.09 g/mol. Therefore, the mass of H3PO4 produced in the reaction is: 4.50 mol H3PO4 * 98.00 g/mol = 434.00 g H3PO4 And the mass of Ca(PO4)2 produced in the reaction is: 4.50 mol Ca(PO4)2 * 212.09 g/mol = 953.41 g Ca(PO4)2 These are the masses of each product that would be produced if 750 mL of 6.00 M H3PO4 reacts according to the given chemical equation.
The chemical formula for phosphoric acid is H3PO4.
One formula unit of FeBr2 contains one iron atom.
In iron bromide FeBr2, there is 1 iron atom present.
Ferrous bromide is FeBr3 Do NOT confuse with Ferric bromide which is FeBr3