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Methane reacts with oxygen in the following way. CH4 + 3 O2 --> CO2 + 4 H2O. If 5 moles of oxygen react with 2.8 moles of methane, only 1.67 moles of methane would be consumed because of the molar ratio 1:3. This would produce 1.67 moles of carbon dioxide and 6.67 moles of water.

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9y ago
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10y ago

5 mol O2 * 1 mol CH4 / 2 mol O2 = 2.5 mol CH4 needed for reaction

Therefore CH4 is the excess reactant and O2 is the limiting reactant

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Q: What is the limiting reactant in combustion of methane is 2.8 moles of methane and 5 moles of oxygen?
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How many molecules of oxygen are needed for the incomplete combustion of one molecule of methane?

Oxygen is NOT a PRODUCT (it is not produced) from the complete combustion of methane, it is a REACTANT (it is used in the reaction). The answer is therefore a mass of zero.


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