Oxygen is NOT a PRODUCT (it is not produced) from the complete combustion of methane, it is a REACTANT (it is used in the reaction). The answer is therefore a mass of zero.
The balanced equation for the combustion of natural gas (methane, CH4) is: CH4 + 2 O2 -> CO2 + 2 H2O This equation shows that one molecule of methane reacts with two molecules of oxygen to produce one molecule of carbon dioxide and two molecules of water.
When methane is burned, one molecule of methane (CH4) reacts with two molecules of oxygen (O2) to produce one molecule of carbon dioxide (CO2) and two molecules of water (H2O). So, for every molecule of methane burned, one molecule of carbon dioxide is produced.
The balanced chemical equation for the reaction CH4 + 2O2 → CO2 + 2H2O shows that one molecule of methane (CH4) reacts with two molecules of oxygen (O2) to produce one molecule of carbon dioxide (CO2) and two molecules of water (H2O). This is a combustion reaction where methane is burned in the presence of oxygen to produce carbon dioxide and water.
The equation CH4 + 2O2 means one molecule of methane (CH4) reacts with two molecules of oxygen (O2) to produce one molecule of carbon dioxide (CO2) and two molecules of water (H2O) in a combustion reaction.
Ammonia is not organic. Others are organic molecules
Incomplete combustion of Methane is....2CH4 + 2O2 --> CO + C + 4H2O
Incomplete combustion of Methane is....2CH4 + 2O2 --> CO + C + 4H2O
no
Burning of methane is:CH4 + 2 O2---------- → CO2 + 2 H2OCarbon monoxide is released after an incomplete combustion.
To react completely with one molecule of methane (CH4), two molecules of oxygen (O2) are needed. This is because the balanced chemical equation for the combustion of methane is CH4 + 2O2 → CO2 + 2H2O. Each molecule of methane requires two molecules of oxygen to form carbon dioxide and water.
The balanced equation for the combustion of natural gas (methane, CH4) is: CH4 + 2 O2 -> CO2 + 2 H2O This equation shows that one molecule of methane reacts with two molecules of oxygen to produce one molecule of carbon dioxide and two molecules of water.
For the complete combustion of methane (CH4), the balanced chemical equation is: CH4 + 2O2 -> CO2 + 2H2O This equation shows that for every mole of methane that reacts, 2 moles of water (H2O) are produced.
no it means it was an incomplete combustion causing pure Carbon (carbon monoxide or sut).
Complete combustion of a hydrocarbon yields carbon dioxide & water; incomplete combustion yields carbon monoxide & water. By having excess oxygen you have enough oxygen to ensure complete combustion. For example the combustion of methane (CH4):complete combustion: CH4 + 2O2 --> CO2 + 2H2Oincomplete combustion: CH4 + 1.5O2 --> CO + 2H2OAs you can see you need a 1/2 mole less of oxygen for the incomplete combustion of methane. So as long as you have twice the amount (in terms of moles) of oxygen as methane you will ensure complete combustion. So anything in excess of that will also ensure complete combustion.
When methane is burned, one molecule of methane (CH4) reacts with two molecules of oxygen (O2) to produce one molecule of carbon dioxide (CO2) and two molecules of water (H2O). So, for every molecule of methane burned, one molecule of carbon dioxide is produced.
The balanced chemical equation for the reaction CH4 + 2O2 → CO2 + 2H2O shows that one molecule of methane (CH4) reacts with two molecules of oxygen (O2) to produce one molecule of carbon dioxide (CO2) and two molecules of water (H2O). This is a combustion reaction where methane is burned in the presence of oxygen to produce carbon dioxide and water.
... will also result in formation of carbon monoxide, formaldehyde (methanal), methanol, carbon black.