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In the complete combustion of C3H8O3 how many moles of carbon dioxide are produced when 23.0g of C3H8O3 burns?
To calculate the moles of CO2 produced during the combustion of C3H8O3, you need to first balance the chemical equation. The balanced equation is C3H8O3 + 4.5O2 -> 3CO2 + 4H2O. Next, calculate the number of moles of C3H8O3 by dividing the given mass by its molar mass (92g/mol). Then, use the stoichiometry of the balanced equation to determine the moles of CO2 produced (3 moles of CO2 for every 1 mole of C3H8O3 burned).
How many moles of oxygen are utilized by the complete combustion of propane?
Propane is C3H8 and the combustion equation is C3H8 + 5O2 ==> 3CO2 + 4H2OSo the complete combustion of 1 mole of propane requires 5 moles of oxygen.
How many grams of carbon dioxide are produced when 23.5 g of 1-heptanol react with excess oxygen in a combustion reaction?
To find the grams of carbon dioxide produced, first determine the moles of 1-heptanol using its molar mass. Then, use the balanced combustion equation of 1-heptanol to find the moles of CO2 produced. Finally, convert moles of CO2 to grams using its molar mass.
How many carbon dioxide molecules are produced for every methane molecule burned?
The result will be 1 m3 of CO2 and 2 m3 of H2O gas (and 2 m3 of O2 will be consumed).This is determined by the stoichiometry of the balanced reaction:CH4 + 2O2 ---> CO2 + 2H2O
How many moles of potassium chlorate must be used to produce 6 moles of oxygen gas?
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
How many moles of steam are produced at 2.00 ATM and 202 degrees C by the complete combustion of 12.50 L og methane gas?
To solve this problem, you would first calculate the moles of methane gas using the ideal gas law. Once you have the moles of methane, you would use the stoichiometry of the combustion reaction to find the moles of steam produced. Finally, you would convert the moles of steam to the appropriate volume at the given conditions of temperature and pressure using the ideal gas law again.
How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
To determine the moles of carbon dioxide produced from the combustion of methane, we first need to balance the chemical equation for the combustion of methane: CH4 + 2O2 → CO2 + 2H2O. From the balanced equation, we see that 1 mole of methane produces 1 mole of carbon dioxide. The molar mass of methane (CH4) is 16.05 g/mol, and the molar mass of carbon dioxide (CO2) is 44.01 g/mol. Therefore, 100.0 grams of methane is equivalent to 100.0 g / 16.05 g/mol = 6.23 moles of methane, which would produce 6.23 moles of carbon dioxide.
How many moles of oxygen will be produced from the complete combustion of 4 moles of propane?
The balanced chemical equation for the combustion of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This means that 5 moles of oxygen are required to completely combust 1 mole of propane. Therefore, 20 moles of oxygen would be produced from the complete combustion of 4 moles of propane.
What mass of water is produced from the complete combustion of 2.50x10-3 of methane?
Methane is CH4. Combustion is CH4 + 2O2 ==> CO2 + 2H2O1 mole CH4 produces 2 moles H2Omoles CH4 used = 1.1x10^-3 g x 1 mole/16 g = 6.875x10^-5 molesmoles H2O produced = 6.875x10^-5 moles CH4 x 2 moles H2O/mole CH4 = 1.375x10^-4 molesmass H2O produced = 1.375x10^-4 moles x 18 g/mole = 2.475x10^-3 g = 2.48 mg (3 sig.figs)
How many moles of carbon dioxide are formed from 14 moles of methane?
When methane undergoes complete combustion, the equation for the reaction is CH4 + 2 O2 -> CO2 + 2 H2O. This shows that the number of moles of carbon dioxide formed are the same as the number of moles of methane reacted, so that 14 moles of carbon dioxide will be formed from 14 moles of methane.
Why does excess supply of oxygen lead to complete combustion?
Complete combustion of a hydrocarbon yields carbon dioxide & water; incomplete combustion yields carbon monoxide & water. By having excess oxygen you have enough oxygen to ensure complete combustion. For example the combustion of methane (CH4):complete combustion: CH4 + 2O2 --> CO2 + 2H2Oincomplete combustion: CH4 + 1.5O2 --> CO + 2H2OAs you can see you need a 1/2 mole less of oxygen for the incomplete combustion of methane. So as long as you have twice the amount (in terms of moles) of oxygen as methane you will ensure complete combustion. So anything in excess of that will also ensure complete combustion.
What mass of carbon dioxide is produced from the complete combustion of 6.80103g of methane?
The balanced equation for the complete combustion of methane is CH4 + 2 O2 -> CO2 + 2 H2O. This equation shows that each mole of methane produces one mole of carbon dioxide. The mass of carbon dioxide produced by complete combustion of any mass of methane will therefore equal the mass of methane reacted multiplied by the ratio of the gram molecular masses of carbon dioxide and methane. The answer to the question therefore is about (6.80103)(44.0098)/(16.04276) or 18.6953 grams of carbon dioxide, to the justified number of significant digits.
How many moles of water are produced from the combustion of 10.00 g of hydrogen?
10,55 moles of water are obtained.
During the complete combustion of pentanol C5H11OH how many grams of water vapor is produced from 420.784 g of pentanol?
chem equation for complete combustion of pentanol is 2C5H11OH (l) + 15O2 (g) => 10CO2 (g) + 12H2O (l) The answer, however, is 95.1069 g of CO2 (with the correct sigfigs). To solve it, set up a mole ratio conversion factor from the equation above. ^
How many moles of hydrogen form when 4 moles of methane react completely?
The complete combustion of methane proceeds according to the equation: CH4 + 2 O2 = CO2 + 2 H2O. Therefore, each mole of methane produces two moles of water and 4 moles of methane will produce eight moles of water.
In the complete combustion of C3H8O3 how many moles of carbon dioxide are produced when 23.0g of C3H8O3 burns?
To calculate the moles of CO2 produced during the combustion of C3H8O3, you need to first balance the chemical equation. The balanced equation is C3H8O3 + 4.5O2 -> 3CO2 + 4H2O. Next, calculate the number of moles of C3H8O3 by dividing the given mass by its molar mass (92g/mol). Then, use the stoichiometry of the balanced equation to determine the moles of CO2 produced (3 moles of CO2 for every 1 mole of C3H8O3 burned).
How many moles of oxygen would be needed for the complete combustion of the 3 moles of the hydrogen?
1 mole
