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First balance the equation of the reaction:

NaOH + HCl ---> NaOH + H2O

The ratio of moles is 1:1

M1V1 = M2V2

(molarity1 x volume1) = (molarity2 x volume2)

M2 = M1V1 / V2

molarity2 = (molarity1 x volume1) / (volume2)

M of HCl = 50M x 0.025 litres / 0.02625 litres

= 47.6 M

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Q: If 25.00ml of 50m naoh is used to titrate 26.25ml of hcl to the equivalence point what is the concentration of the hcl?
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