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If 3.5 L of a 5.0 M SrCl2 solution is diluted to 45 L what is the molarity of the diluted solution?
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What's the molarity of 257 mL of a solution if 35 00 grams of ammonium phosphate were dissolved in the solution?
35 g-----------------257 mLx g------------------1 000 mLx = (1000 x 35)/257 = 136,18 g149,09 g------------------1 mol136,18 g------------------x molx = 136,18/149,09 = 0,91 mol149,09 is the molar mass of ammonium phosphate.
What are two physical properties of salt water?
- freezing point for a solution of 35 g/L NaCl: -2 deg. Celsius- density for a solution of 35 g/L NaCl: 1,025 g/cm3- thermal conductivity for a solution of 35 g/L NaCl: 0,6 W/m.K
How do you solve this chemistry question?
if 200 mL of 0.2 M of zinc hydroxide is diluted to a point where its volume increase by 35% what is the OH concentration?I got 0.29 M which is probably not right
What is the equilibrium vapor pressure at 35 Celsius above a solution of 3.80 moles of volatile C6H12 in 8.20 moles of C5H10O?
154 psi
What is the boiling point of a solution of 1250 g of c6h12o6 in 350 g c2h5oh kb for c2h5oh is 119cm and the boiling point of c2h5oh is 78c?
35 c
What is the molarity of sodium sulphate in a solution prepared by dissolving 15.5g in enough water to make 35ml of solution?
Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )
What is the molarity of 35 per cent Hydrochloric acid solution with specific gravity of 1.8 gram per liter?
It is 11.3
How do you calculate the molarity of the solution composed of 2.60 grams of NaCl in a total volume of 35 mL of solution?
Molarity means the number of mol of a substance per 1 litre of substance. Or figure out the number of mol of NaCl ((2.60/(23+35)=0.04) then multiply the 35ml by 28.571428 to get that to litres.. then multiply the number of mol by 28.571428 to get that to the number of mol. Therefore the answer is 1.142857M. See the Related Questions link "How do you prepare a solution of a specific concentration?"
What's the molarity of 257 mL of a solution if 35 00 grams of ammonium phosphate were dissolved in the solution?
35 g-----------------257 mLx g------------------1 000 mLx = (1000 x 35)/257 = 136,18 g149,09 g------------------1 mol136,18 g------------------x molx = 136,18/149,09 = 0,91 mol149,09 is the molar mass of ammonium phosphate.
What is the molarity of 32 percent HCl?
A: 10.172 M HCl. Percents of acids like this one is normally given in % w/w, or percent weight by weight. So we need to find the mass of the solution. Molarity is moles of solute per liter solution, so we will calculate this for 1L of solution. The density of 32% HCl is 1.159 g/mL. So assuming we have one liter or 1000 mL, the weight of the solution is 1159 g. If 32% of this is HCl, we have 1159 g solution * 0.32 g HCl/g solution = 370.88 g HCl. The molar mass of HCl is 36.461 g/mol, so 370.88 g HCl * 1 mol HCl/36.461 g HCl = 10.172 mol HCl in 1 L of solution. 10.172 mol HCl/1L solution = 10.172 M HCl.
What is the solution for 35 percent of 60?
35% of 60= 35% * 60= 0.35 * 60= 21
What percentage of 200 is 70?
The answer is 35%. Solution: 70/200x100 =0.35x100 =35%
What is the solution to 6x-7 equals 35?
If 6x-7=35 then 6x=35+7=42 and x=7
What is the equation of 5y equals 35?
The equation is [ 5y = 35 ].The solution to the equation is [ y = 7 ].
What is the solution of a plus 35 equals 51?
a = 16
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The amount of water added to the HCl to aid titration could have been 35 mL or 45 mL and would have given the same results as with the approximately 10 mL you used Ex?
during acid base titration a base reacts with acid molecules not with water so when 35 ml solution is diluted with water the no of molecules of acid remains the same.... so reading does not changed...
