-3x + 4y = 12 Temporary value of y: 4y = 3x + 12 y = (3x + 12) / 4 Substituting y: -3x + 4 [(3x+12) / 4] = 12 -3x + 12x + 48 = 12 -3x + 12x = 12 - 48 9x = 12 - 48 9x = -36 x = -36 / 9 x = -4 Subtituting x to get the final value of y: -3(-4) + 4y = 12 12 + 4y = 12 4y = 12 - 12 4y = 0 y = 0 Final answer: x = -4 y = 0 Check: -3x + 4y = 12 -3(-4) + 4(0) = 12 12 + 0 = 12 12 = 12 Solution 2: -3x + 4y = 12 Temporay value of x: 3x = 4y - 12 x = (4y - 12) / 3 Substituting x to get the value of y: 3[(4y - 12) / 3] + 4y = 12 12y - 36 + 4y = 12 16y = 12 + 36 16y = 48 y = 48 / 16 y = 3 Substituting y to get the value of x: -3x + 4(3) = 12 -3x + 12 = 12 -3x = 12 - 12 x = 0 Final Answer: x = 0 y = 3 Check: -3(0) + 4(3) = 12 12 = 12
3(4y+5) = 25 3 . 4y + 3 . 5 = 25 12 y + 15 = 25 12 y = 25 - 15 12 y = 10 y = 12:10 = 1.2
assuming that the question is asking 4y = 48, y = 12
4y - 8x + 12 = 0 4y = 8x - 12 y = 2x - 3 So the slope = 2 y-intercept = -3
4y + 7 = 19 ∴ 4y = 12 ∴ y = 3
when y = 3, 8y-4y = 4y = 4*3 = 12
4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4
4y-8x = 12 4y = 8x+12 y = 2x+3 So the slope is 2 and the y intercept is 3
4y-8x+12 = 0 4y = 8x-12 y = 2x-3 The slope is 2 and the y intercept is -3
4y + 10 = 22 4y - 10 - 10 4y=12 4y 4y 4y=3
Factor out the 4. The answer is y-3/y+3
12-4y=y-3 (subtract 12 from both sides) -4y=y-15 (subtract y from both sides) -5y=-15 (multiply both sides by -1 to make them positive) 5y=15 (divide by 5) y=3