The number of water molecules obtained is 120,44281714.10e23.
1.2x10^25
5048+w4g5=23vm32
C3H8 (butane) + 5 O2 (oxygen) --> 3 CO2 (carbon dioxide) + 4 H2O (water)
Burning propane is called combustion, in which propane combines with oxygen to form carbon dioxide and water.
C3H8 is a non-electrolyte. This is considered as an organic compound that does not readily ionize when dissolved or melted. It is also a poor conductor of electricity.
1.2x10^25
5048+w4g5=23vm32
You have to burn C3H8 in O2. You get 3CO2 plus 4H2O. So to burn one mole of C3H8, you need 5 moles of O2. That means you need one fifth of C3H8 as compared to O2. So you need 0.567/5 = 0.1134 moles of C3H8. Hence the answer.
Out of one mole C3H8 three moles carbondioxide (CO2) are formed by complete combustion of it.So 2.13 mole C3H8 make 3*2.13 mole CO2 = 6.39 moleCO2
Propane has three carbons and this is it's molecular structure: C3H8.
C3H8 + 5O2 >> 3CO2 + 4H2O ( and, of course, energy )
The reaction between C3H8 (propane) and oxygen gas is a combustion reaction. The products of combustion reactions are always carbon dioxide (CO2) and water (H2O) the reaction looks like this: C3H8 + 5O2 -> 3CO2 + 4H2O
By the definition of Avogadro's Number, each mole contains 6.022 X 1023 molecules. Therefore, (9.25 X 1024)/(6.022 X 1023) or 15.4 moles are required, to the justified number of significant digits.
C3H8 (butane) + 5 O2 (oxygen) --> 3 CO2 (carbon dioxide) + 4 H2O (water)
Propane ( C3H8 ) Will burn completely in excess oxygen to form water and carbon dioxide;C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
Burning propane is called combustion, in which propane combines with oxygen to form carbon dioxide and water.
Yes it is ..... Its Propane (C3H8)