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The frequency of dominant which is smooth seed early is 0.556 or 6%.
If one parent is homozygous dominant for all traits (carrying two dominant alleles for each trait), and the other parent is heterozygous (carrying one dominant and one recessive allele for each trait), there would be a 100% chance that the baby would inherit the dominant alleles from the homozygous dominant parent. Therefore, the baby would also be heterozygous for all the traits, carrying one dominant and one recessive allele for each trait.
R R r Rr Rr r Rr Rr That is the Punnet Square. The genotype will be 100% Rr in the cross. The phenotype will be whatever phenotype is constituted by your dominant allele.
A sex linked dominant trait could be on the X chromosome of either parent and the phenotype of any individual carrier would be that of the dominant trait. A father with the dominant characteristic on his single X chromosome would produce daughters that are 100% carriers and would not pass the characteristic on to his sons. A mother who is a dominant X linked carrier would pass the dominant characteristic on to half hersons and half her daughters all of which would show the trait phenotypically. A sex linked recessive father would produce 100% carrier daughters. His sons would not get the recessive allele from him. A sex linked recessive carrier (heterozygous) mother would pass the trait on to 50% of her children and 50% of her sons would show the recessive trait genetics.
there would be a 100% chance of it being heterozygous (Pp)
A. 0.45 Apex
, 0.34 Apex
0.34 (cst)
.77
0.16
The frequency of dominant which is smooth seed early is 0.556 or 6%.
If one parent is homozygous dominant for all traits (carrying two dominant alleles for each trait), and the other parent is heterozygous (carrying one dominant and one recessive allele for each trait), there would be a 100% chance that the baby would inherit the dominant alleles from the homozygous dominant parent. Therefore, the baby would also be heterozygous for all the traits, carrying one dominant and one recessive allele for each trait.
A cross between two homozygous parents will form a 100 percent chance of a heterozygous offspring. One homozygous parent must have the dominant allele, and the other must have the recessive allele. So, if the circumstances are correct, these characteristics will make for a 100 percent chance of a heterozygous offspring.
R R r Rr Rr r Rr Rr That is the Punnet Square. The genotype will be 100% Rr in the cross. The phenotype will be whatever phenotype is constituted by your dominant allele.
100% is represented by percent.
An allele present in all members of a population
If the allele for solid is: ee The allele for spotted is:Ee An the Allele for charlie (very lightly spotted) is: EE Than with a solid and a spotted you will get: 50% spotted and 50% solid Two spotteds get:25% charlie 50% spotted and 25% solid Charlie and Solid get: 100% broken charlie and charlie get: 100% charlie solid and solid get 100% solid Over all charlie is most dominant, but spotted is dominant to solid