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If a 0.001 and a 0.015 capacitor are placed in parallel. what would be the total capacitance of the circuit?
Wiki User
∙ 14y ago
Let C1=0.05F
& C2=0.025F, C1 & C2 are in series
Let the equivalent capacitance will be C
than 1/C = 1/C1 + 1/C2
1/C = 1/0.05 + 1/0.025 = 20 + 40 = 60F
hence C= 1/60 = 0.0166667 F
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoIf a 0.001 and a 0.015 capacitor are placed in parallel, the total capacitance of the circuit would be 0.016.
Capacitors in parallel simply add, just like resistors in series add.
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