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What happens in a animal cell in pure water an why does this not happen in a plant cell?
It can possibly burst.
Will an animal cell shrink if placed in pure water?
No, an animal cell will not shrink if placed in pure water. Instead, it will tend to swell and may eventually burst due to the process of osmosis, where water moves into the cell to equalize the concentration of solutes inside and outside the cell.
Why animal cells burst when they are placed in pure water?
Animal cell are hypertonic to the water i.e. they have more solute concentration inside the cell when placed in pure water. Now by the law solvent(water here) move from low concentration of solute to high concentration of solute so water move inside the animal cell which make cell to swell up and when the swelling pressure increase then wall pressure the cell get burst
What happens if a cell is placed in a pure water?
In this case the solution is hypotonic in relation to the cell. The cell swells up and ruptures as the water rushes in, and since the animal cell has no cell wall it cannot become turgid (stop letting in water), therefore the cell will rupture.
What happens to a animal cell in pure water an explain Why this does not happen in a plant cell?
Similar to placing an animal cell into water, the cell will swell and could burst, depending on the rigidity of the cell wall. This occurs because the osmotic pressure from dissolved solids is greater inside the cell than in the water. This osmotic pressure would then allow a passive diffusion of water into the area of greater solute density and thus expand the volume of the cell until equilibration or bursting.
What can happen if a cell placed in pure water 100 percent?
If a cell is placed in pure water, the water will move into the cell through osmosis, causing it to swell and potentially burst. This process is known as cytolysis and can result in cell death.
What would happen if a cell containing many solutes was placed in a pure water?
We wouled all die
If you place a blood cell in a beaker filled with pure water what would happen?
If a blood cell is placed in a beaker filled with pure water, it will undergo osmosis, leading to the movement of water into the cell. This influx of water causes the cell to swell and can eventually result in the cell bursting, a process known as hemolysis, due to the difference in osmotic pressure between the inside of the cell and the surrounding water.
What would happen if a normal cell were placed in a beaker of pure water?
it would absorb more and more water until it will explode
What would happen if a cell containing many disolved solutes was placed in pure water?
The cell would undergo osmosis, which is the movement of water from an area of high concentration (pure water outside the cell) to an area of low concentration (inside the cell with dissolved solutes). This would cause the cell to swell and potentially burst if the water influx is too rapid.
What would happen if a living cell was placed into pure water?
Because the water is pure, the water outside will follow the concentration gradient of osmosis (from high concentration to low concentration). Since the percentage of solutes is much lower (in fact it's not even there in pure water) and the water concentration is much higher, ergo it'll flow into the cell to balance out the concentration. This causes the cell to swell, and eventually burst, or lyse.
What would happen if a cell containing dissolved solute was place in pure water?
Water would enter the cell by osmosis in order to equalize the solute concentration/water concentration between inside and outside. The cell would tend to rupture.
