there is a 50% chance that the child will be colorblind. If it is a boy, it will be colorblind, but if it is a girl, it will only be a carrier. Mother's chromosome is XrXr and Father's Chromosome is XRY, which means the children's genotypes will be XRXr if girl and XrY if a boy.
Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.
It is not impact our vision.
Color blindness typically does not affect life expectancy. It is a hereditary condition that primarily impacts the way individuals perceive colors. People with color blindness can lead normal, healthy lives without any impact on their overall life expectancy.
Yes.
The probability is 0 (but the daughter will be a carrier of the color blind gene). This is because the gene dictating whether someone is color blind or not is linked to the X chromosome (and not the Y). The color blind gene is a recessive gene whilst the normal color vision gene is a dominant gene. Hence if a girl (XX) has one normal vision gene (from one parent) and one color blind gene (from the other parent), her normal vision gene will be dominant to the recessive color blind gene and hence she will have normal vision (but she will be a carrier of the color blind gene). If both her parents contribute the recessive color blind gene to her, then she will be color blind. For a woman (XX) to be color blind, she needs to be have both genes to be recessive (ie where there is no dominant normal color vision gene to dominate). For a man (XY), as long as the X gene contributed by his mother is a color blind gene, he will be color blind because he has no other X chromosome where a dominant normal color gene could reside. Hence, to answer the question, a man with normal color vision (XY, with a dominant normal color vision X gene since the gene can't be the recessive color blind gene otherwise he will be colorblind) and a colorblind woman (XX, both recessive color blind genes), will each contribute an X each the child. The man will contribute his only X chromosome which carries the normal color vision X gene and the woman can only contribute a recessive color blind gene. The man's normal color vision X gene will be dominant, and hence the daughter will definitely have normal vision (despite being a carrier).
The mother has two defective X chromosomes for color. The father has a normal X (and Y). If they have children and they are girls, the girls will have one defective X and a normal X. That normal X from dad will be enough so she will see color. If a boy, he will have a defective X and a normal Y but will be color blind. Only in the case of one normal X and a defective X would a child have normal vision. The Y chromosome doesn't have any genes for color.
50%
No they will produce a child who is colour blind.
The phenotypic ratio will be 1:3.his son will be color blind.
20/200 means you can only see at 20 feet what a person with normal vision can see at 200 feet. Therefore you would be legally blind.
It's not normal to be blind unless your eye is swollen shut. But it's common to have blurred vision.
50%. 1 of the two male offspring will definately be color blind. Do a punnett square with the father having normal vision and the mother being a carrier.