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force x distance force=9800n distance=250m 9800 x 250= 2450000 Mega Joutes
Work = force x distance = 200 joules
Work done equals force times distance, so 10.0 times 0.9 is 9 joules.
work=force(distance) work=500(20) work=10000 joules
Just multiply the force times the distance. The answer is in joules.
force x distance force=9800n distance=250m 9800 x 250= 2450000 Mega Joutes
Work = force x distance = 200 joules
Work done equals force times distance, so 10.0 times 0.9 is 9 joules.
work=force(distance) work=500(20) work=10000 joules
Just multiply the force times the distance. The answer is in joules.
force=2N distance moved=o.1 m work done=? work done=force(N)*distance moved (M) work done=2*o.1 work done= 0.2 watts
24000 joules
You are supposed to multiply force x distance.
The force required to lift the object is much less than otherwise. One might see this surprising. How the use of a ramp can decrease the force required to lift an object? The answer is that the distance the object has to moved is longer. This means that the work done in both cases is the same.(assuming there is no resistive forces) (Work done = Force x distance moved in the direction of the force) In practice however, due to friction, the total work done may actually be greater, but the decrease in the applied force is indeed worth it. A system of pulleys also uses this principle, as well as hydraulic systems.
Work is force times displacement (distance). Thus, about 3 work is being done. The unit depends on the unit of the work and distance. If the work unit is Joules, and the distance unit is meters, then the force unit would be Newtons.
Work = force x distance Work = 10N x 4m= 40 joules
Work = force x distance. Answer is in joules.