The resulting offspring will be 25% tall homozygous, 25% short homozygous, or 50% heterozygous. Depending on the gene, the heterozygous will either have codominance, incomplete dominance, normal dominance depending on which gene is dominantly expressed.
put TT on top of the box then put tt on the side and divide the box into 4 pieces then the top left box with be TT and the top right will be Tt and the bottom left will be Tt and the bottom right will be tt then it will be 75% tall and 25% short
You will get plants whose phenotype, or appearance, is tall, but whose genotype, or genetic makeup, has one tall gene and one short gene. If T=tall and t=short, all of the resulting plants will have the genotype Tt. They appear to be tall because the tall gene is dominant over the short gene, but can still pass the short gene on if they are crossed with other pea plants.
TT x tt
all offspring will be Tt (heterozygous) genotype and tall phenotype
the phenotype of it is heterozygous tall
because T is dominant over t!.....
the recessive trait seems to disappear
the recessive trait seems to disappear
You get all tall pea plants.
the recessive trait seems to disappear
In such a cross, the F1 plants will always be tall, because that is the dominant allele. In the cross described, a homozygous dominant plant was crossed with a homozygous recessive plant; a cross that produces 100% heterozygous offspring. (AaBbCc)
the tall plant must be heterozygous
Homozygous dominant would be all Capital letters. Homozygous recessive would be all lower case letters. So...in basic color genetics for horses: A homozygous recessive horse would be aaee A homozygous dominant horse would be AAEE
Presuming tall is a dominant allele (the 2nd parent is heterozygous and "tall" is it's phenotype), then the square would be as follows: Let T be the dominant gene for tall, and thus every genotype containing this (TT, or Tt) would produce a tall plant. Let t be recessive, and in the absence of T (tt) causes a plant to be small. So the homozygous tall parent would be TT, and the heterozygous tall parent would be Tt. So now you just have to cross them. During meiosis, every gamete from the TT genotype would contain a T allele. However, for the Tt genotype, there is equal chance each gamete will contain EITHER a T or a t. So the square would be: xxTxxT TxTTxTT txTtxTt As you can see, 2 out of the 4 offspring have a Tt genotype (heterozygous), so this translates to a 1/2 fraction, or 50%. Ignore the Xs in the table- if i just used spaces then all the letters crunched up on top of each other when i pressed save...it was the best i could do...:S
If a heterozygous tall pea plant, Aa, is crossed with a homozygous plant, AA, for the trait, you will have a one in one in four chance of the offspring being heterozygous. You will need to create a square and plug the traits in to see what the odds are.
0 (there is no chance it will be short since tall is dominant over short). Hope this helps! - Biology Student
In such a cross, the F1 plants will always be tall, because that is the dominant allele. In the cross described, a homozygous dominant plant was crossed with a homozygous recessive plant; a cross that produces 100% heterozygous offspring. (AaBbCc)
there is a 50% chance that the offspring will be tall.
Not if either trait is dominant. Let us say tall is dominant ( I think it is ) and short is recessive. T = tall, and s = short. TT X ss will give heterozygous tall plants. Ts
Dominant Allele
the tall plant must be heterozygous
Homozygous for tall is TT Homozygous for short is tt All F1 offspring from this cross are Tt which makes them genotypically heterozygous and phenotypically tall.
one tall allele and one short allele
When Gregor Mindel crossed homozygous tall plants with homozygous short plants,he got hetrozygous tall plants. Tall plants will dominate any small pea plants in the same area.The traits for tall were dominant over short traits. Perhaps both alleles can code for protein, but the dominant product is expressed in the phenotype.
If a plant is homozygous tall then it would possess two tall genes instead of a short gene. If for the notation you use B to represent the dominant tall gene and b to represent the recessive short gene the plant would carry and "BB" compliment of genes.
They inherited a T (tall) allele from the tall parent, and a t (short) allele from the short parent. This is only if we assume that both parents are homozygous, which the short parent would need to be for the short trait to show. If this is true, then the F1 generation would show the tall trait 4/4 times, and would end up with the genotype Tt 4/4 times.
Homozygous dominant would be all Capital letters. Homozygous recessive would be all lower case letters. So...in basic color genetics for horses: A homozygous recessive horse would be aaee A homozygous dominant horse would be AAEE