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Homozygous dominant would be all Capital letters.

Homozygous recessive would be all lower case letters.

So...in basic color genetics for horses:

A homozygous recessive horse would be aaee

A homozygous dominant horse would be AAEE

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What is the offspring if you cross two heterozygous Tt tall plants?

You get one homozygous dominant (TT), one homozygous recessive (tt), and two heterozygous (Tt).


What kind of offspring will a homozygous tall plant and a homozygous short plant have?

Presuming tall is a dominant allele (the 2nd parent is heterozygous and "tall" is it's phenotype), then the square would be as follows: Let T be the dominant gene for tall, and thus every genotype containing this (TT, or Tt) would produce a tall plant. Let t be recessive, and in the absence of T (tt) causes a plant to be small. So the homozygous tall parent would be TT, and the heterozygous tall parent would be Tt. So now you just have to cross them. During meiosis, every gamete from the TT genotype would contain a T allele. However, for the Tt genotype, there is equal chance each gamete will contain EITHER a T or a t. So the square would be: xxTxxT TxTTxTT txTtxTt As you can see, 2 out of the 4 offspring have a Tt genotype (heterozygous), so this translates to a 1/2 fraction, or 50%. Ignore the Xs in the table- if i just used spaces then all the letters crunched up on top of each other when i pressed save...it was the best i could do...:S


What does it mean if a plant is true breeding?

Mendel started out with plants that "bred true". That is, when tall plants were self-pollinated (or cross-pollinated with others like them), plants in following generations were all tall; when the short plants were self-pollinated (or cross- pollinated with others like them) the plants in following generations were all short.


In pea plants the allele for tallness is dominant. What are the possible genotypes of a tall pea plant?

the tall plant must be heterozygous


If a homozygous dominant plant crossed with a homozygous recessive plant what is the genotype and phenotype of their offspring?

If two homozygous plants with contrasting traits are crossed, the expected genotypes for the offspring will be heterozygous. The dominant trait would be expressed, but they'd be carriers for the recessive trait.

Related Questions

WHAT DO THE LETTERS ON INSIDE OF THE PUNNET SQUARE STAND FOR?

Using Punnett Squares, you can predict the genotypes and phenotypes of the offspring of a cross between a homozygous (purebred) tall pea plant and a homozygous (purebred) short pea plant.


What do the letters on the inside of the punnets square stand for?

Using Punnett Squares, you can predict the genotypes and phenotypes of the offspring of a cross between a homozygous (purebred) tall pea plant and a homozygous (purebred) short pea plant.


What do the letters on the inside of the punnet square stands for?

Using Punnett Squares, you can predict the genotypes and phenotypes of the offspring of a cross between a homozygous (purebred) tall pea plant and a homozygous (purebred) short pea plant.


In a certain species plant the allele for tallness is dominant over the allele for shortness.to determine wether a tall plant is heterozygous should be crossed with a?

To determine whether a tall plant is heterozygous, it should be crossed with a homozygous recessive plant (short plant). If any offspring are short, the tall plant must be heterozygous; if all offspring are tall, the tall plant is likely homozygous dominant. This test cross allows for the observation of inheritance patterns in the offspring.


What is the offspring if you cross two heterozygous Tt tall plants?

You get one homozygous dominant (TT), one homozygous recessive (tt), and two heterozygous (Tt).


When a tall homozygous plant was crossed with a short homozygous plant the F1 offspring were all tall. No short plants were present in the F1 generation. Which principle does this situation represent?

This situation represents Mendel's principle of dominance. In this cross, the tall allele is dominant over the short allele, resulting in all F1 offspring exhibiting the tall phenotype. Since both parent plants are homozygous, the F1 generation inherits one tall allele from the tall parent and one short allele from the short parent, but only the dominant tall trait is expressed.


When model crossed true-breeding tall plants with true-breeding short plants all of the offspring were tall because?

Homozygous for tall is TT Homozygous for short is tt All F1 offspring from this cross are Tt which makes them genotypically heterozygous and phenotypically tall.


What letters can be used to model Mendels cross of true-breeding tall plants what true-breeding short plants in a Punnett square?

TT for the homozygous tall parent, tt for the homozygous short parent and Tt for the heterozygous offspring.


In certain plants tall is dominant to short If a heterozygous plant is crossed with a homozygous tall plant what is the probability that the offspring will be short?

0 (there is no chance it will be short since tall is dominant over short). Hope this helps! - Biology Student


Paul decides to cross his long haired guinea pig with a short haired guinea pigBoth were homozygous for their traitWhat is the genotypic ratio of the offspring?

The offspring will look more like the mom but they will have mid hair.


If a true breeding tall pea plant is crossed with a tall pea plant of unknown percentage is correct?

When a true breeding tall pea plant (homozygous for the tall trait, TT) is crossed with a tall pea plant of unknown genotype, the offspring's phenotypes can help determine the genotype of the second plant. If all offspring are tall, the unknown plant is likely also homozygous tall (TT). However, if some offspring are short, the unknown plant must be heterozygous (Tt), as the short trait (tt) can only appear if the recessive allele is present. In summary, the resulting phenotypes of the offspring will clarify the genotype of the unknown parent.


What kind of offspring will a homozygous tall plant and a homozygous short plant have?

Presuming tall is a dominant allele (the 2nd parent is heterozygous and "tall" is it's phenotype), then the square would be as follows: Let T be the dominant gene for tall, and thus every genotype containing this (TT, or Tt) would produce a tall plant. Let t be recessive, and in the absence of T (tt) causes a plant to be small. So the homozygous tall parent would be TT, and the heterozygous tall parent would be Tt. So now you just have to cross them. During meiosis, every gamete from the TT genotype would contain a T allele. However, for the Tt genotype, there is equal chance each gamete will contain EITHER a T or a t. So the square would be: xxTxxT TxTTxTT txTtxTt As you can see, 2 out of the 4 offspring have a Tt genotype (heterozygous), so this translates to a 1/2 fraction, or 50%. Ignore the Xs in the table- if i just used spaces then all the letters crunched up on top of each other when i pressed save...it was the best i could do...:S