You get one homozygous dominant (TT), one homozygous recessive (tt), and two heterozygous (Tt).
Using a Punnett square, we can predict that 3 out of the 4 offspring will be tall if both parent plants are heterozygous for the tall trait (Tt x Tt). This is based on the 3:1 phenotypic ratio expected from a monohybrid cross.
An F1 x F1 cross would be a cross between heterozygous (Tt) parents. The offspring would be 1/4 TT, 1/2 Tt, and 1/4 tt. This would mean that 3/4 of the offspring would be tall, and 1/4 would be short.These offspring would be the F2 generation. Click on the related link to see an illustration of this using Punnett squares.
In the offspring generation from crossing two pea plants with TT genotypes, all the offspring will have the genotype Tt. However, all of these offspring will be tall since the tall trait is dominant (T) over the short trait (t). Therefore, there will be no short tt plants in the new generation.
If a heterozygous tall pea plant, Aa, is crossed with a homozygous plant, AA, for the trait, you will have a one in one in four chance of the offspring being heterozygous. You will need to create a square and plug the traits in to see what the odds are.
Both the tall plant and short plant must be heterozygous for the height trait, meaning they each carry one dominant and one recessive allele. When they produce offspring, there is a 25% chance of obtaining a short plant by inheriting two recessive alleles for the height trait.
Homozygous for tall is TT Homozygous for short is tt All F1 offspring from this cross are Tt which makes them genotypically heterozygous and phenotypically tall.
Using a Punnett square, we can predict that 3 out of the 4 offspring will be tall if both parent plants are heterozygous for the tall trait (Tt x Tt). This is based on the 3:1 phenotypic ratio expected from a monohybrid cross.
The genotype of the tall pea plant is heterozygous
TT for the homozygous tall parent, tt for the homozygous short parent and Tt for the heterozygous offspring.
An F1 x F1 cross would be a cross between heterozygous (Tt) parents. The offspring would be 1/4 TT, 1/2 Tt, and 1/4 tt. This would mean that 3/4 of the offspring would be tall, and 1/4 would be short.These offspring would be the F2 generation. Click on the related link to see an illustration of this using Punnett squares.
To determine whether a tall plant is heterozygous, it should be crossed with a homozygous recessive plant (short plant). If any offspring are short, the tall plant must be heterozygous; if all offspring are tall, the tall plant is likely homozygous dominant. This test cross allows for the observation of inheritance patterns in the offspring.
In the offspring generation from crossing two pea plants with TT genotypes, all the offspring will have the genotype Tt. However, all of these offspring will be tall since the tall trait is dominant (T) over the short trait (t). Therefore, there will be no short tt plants in the new generation.
there is a 50% chance that the offspring will be tall.
The Punnett square would show that all offspring would be heterozygous for the trait, meaning they would have one allele for tall plants and one allele for short plants. This would result in all offspring being tall plants phenotypically, but carrying the allele for short plants.
the tall plant must be heterozygous.
If a heterozygous tall pea plant, Aa, is crossed with a homozygous plant, AA, for the trait, you will have a one in one in four chance of the offspring being heterozygous. You will need to create a square and plug the traits in to see what the odds are.
The tall plant must be heterozygous.