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If a toy car with a resistance of 2 ohms is connected to a 3v battery how much current flows through the car?
Wiki User
∙ 14y ago
Ohm's Law: V = IR (voltage = current times resistance).
Ohm's Law: V = IR (voltage = current times resistance).
Ohm's Law: V = IR (voltage = current times resistance).
Ohm's Law: V = IR (voltage = current times resistance).
Wiki User
∙ 14y ago
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How will you describe the graph of resistance against current?
If resistance is high that time the current flow is low. Bcoz current always flow through the low resistance path.
A 3 Volt battery sends a current of 0.10 A through a light bulb what is the resistance of the filament of the bulb?
Volt (V) = Resistance (R) times Current (I) therefor R = V / I 30 Ω = 3V / 0.1A
If a 9volt battery produces a current of 3amps through a load the resistance of the load is?
3 ohms. 9 volts across a 3 ohm resistor becomes 9/3 or 3 amps.
What is electronic resister?
Electronics resistor are a basic passive element it oppose the flow of current . the opposition depend upon the value of that resistance high value resistance will only able to flow some few amount of current through them. but low value of resistance allow to flow large current through them.
What is the voltage of a battery if it is connected across an 8 ohm resistor and 0.75 amps of current flows through the resistor?
The battery has 6 volts across its terminals. The way to discover it is to apply Ohm's law. It (Ohm's law) comes in 3 "flavors" that look a bit different but all say exactly the same thing. Here they are: E = I x R [Voltage equals current times resistance.] I = E/R [Current equals voltage divided by resistance.] R = E/I [Resistance equals voltage divided by current.] In these equations, voltage is E, current is I and resistance is R. They are measured in units of volts, amperes (or amps) and ohms, respectively. In your problem, we have the resistance (R) and the current (I). We need to find the voltage (E), and the formula E = I x R is the logical choice to discover the voltage. As E = I x R here, E = 0.75 x 8 = 3/4 x 8 = 6 volts. Piece of cake.
A wire with resistance R is connected to the terminals of a 30 V battery. What is the current through the wire if the wire has the resistance?
Your current will be 30/R Amps. Where R is the resistance in Ohms.
1 A current of 0.88 A flows through a lamp when it is connected in series with a 6 V battery What is the resistance of the lamp?
The formula you are looking for is R = E/I. Resistance is stated in ohms.
What will happen if battery is shorted and grounded?
If a battery is "shorted", meaning that its terminals are connected together through a low resistance, high current flows in the connection and the battery becomes discharged very soon. It makes no difference whether any part of the battery is connected to ground.
When a multimeter is set to measure resistance?
it determines how well the current flows through the wires. ANSWER: When there is no outside power connected to it. But some power is necessary to read the resistance so the meter battery will supply the current necessary to measure the IR drop and translate that to resistance
A 9.0 volt battery connected to bulb. if a current of 0.25 Amps flows through bulb what is the resistance of bulb?
V = IR Voltage = Current * Resistance so 9 = 0.25 * R Hence R =36 Ohms
A resistance of 10 ohms is placed across a 9 volt battery what current flows through the battery?
No current flows through the battery. There is a current through the external circuit. I = E/R = 9/10 = 0.9 amperes.
Why do you have specific resistance combination inside a voltmeter and an ammeter Explain?
in voltmeter we have internal Resistance and connected in series , to current don't transfer in voltmeter , and we have internal resistance in ammeter and connected in parallel , to most current transfer through the ammeter.
Why shunt resistance is used ammeter?
A shunt resistance is a low resistance connected parallel to the galvanometer so that a large portion of current passes through the low resistance and a small fraction of current passes through the galvanometer this saves the galvanometer from damage
If a 1.5 V battery is connected in a simple curcuit to a light bulb with a resistance of 8 ohms the amount of current flowing through the curcuit is?
V = I * R. 1.5 = 8*IThe current flow is 3/16 Amps.
Three identical resistors each 45 ohms are connected in parallel across a 60-V battery The current through or drawn from the battery is?
If 3 identical 45-ohm resistors are connected in parallel, the net effective resistance of the bunch ...and the load seen by the battery ... is 15 ohms. The current supplied by the battery is60/15 = 4 Amperes.(This assumes that the battery is capable of supplying 4 amps at 60 volts, or 240 watts !)
Why do batteries get warm?
Because they have internal resistance. Current flow through this internal resistance produces heat, just like current flow through ordinary resistors does. The current can be from use of the battery or charging the battery (if it is rechargeable). Usually the internal resistance of a battery increases with age, meaning older batteries tend to run hotter than fresh ones.
A copper wire was left connected from one terminal of a battery to the other The wire became very hot Why did the wire get so hot?
The wire acted as the load across the battery terminals. Small short pieces of wire have a very low resistance. Ohms law states I = E/R. Current is directly proportional to the voltage and inversely proportional to the resistance of the circuit. So in other words if the resistance goes low the current (amperage goes high) It is this high current flowing through the wire that makes the wire hot. The higher the resistance the less of a current flow through the wire.
