The equation that you are looking for is Watts = Amps x Volts. Power is consumed at that rate over a time constant. You are billed by the electrical utility company by the kWh. 1000 watts are equal to 1 kW.
1100 watts is used.
First of all the power consumed is only dependent on the load (eg. any appliance) connected to the source. A load will always draw its rated power. If you have increased your voltage to twice then the current drawn by the device will become half but the power consumed will remain same.the power consumed is given by:P= V*I* cos(fi)here for a given load P(power), cos(fi) are constants.Then if V becomes 2V then current will be I/2.
You just need the voltage and the current. Watts = Amps x Volts.
No. You need a 3-phase supply that matches the voltage and current rating of your appliance.
No
Kilo simply means 1000. Volt-ampere (VA) is a measure of power, similar to the watt. Volt is a measure of voltage, or electrical pressure. Voltage means electricity is available, but unless it is actually used, no current (amperes) flows, and no work (power) is done. Suppose you have a motor that needs 1000 volts to run, and when it is on it draws one ampere (amp) of current. We would say the motor supply voltage is one kilovolt. When the motor is running, we would say it uses one kilovolt-ampere (1KVA) of power (1 ampere * 1000 volts = 1000 VA or 1 KVA).
Power consumed by an electrical appliance will increase with a reduction of applied voltage.
Power consumed by the appliance = (DC supply voltage) x (DC current)
There are a number of ways to calculate that current, from which you're free to select the most convenient one. Here are a couple of them: Current = (the mains voltage)/(resistance of the appliance) Current = square root of (power consumed by the appliance/resistance of the appliance)
First of all the power consumed is only dependent on the load (eg. any appliance) connected to the source. A load will always draw its rated power. If you have increased your voltage to twice then the current drawn by the device will become half but the power consumed will remain same.the power consumed is given by:P= V*I* cos(fi)here for a given load P(power), cos(fi) are constants.Then if V becomes 2V then current will be I/2.
It depends on the appliance. All appliances are required to have a 'nameplate' which contains information on their power and voltage ratings.
To answer this question I have to know what you are charged per Kw/hr by the power company. If you mean .10911 per kw/hr, then I need to know at what voltage.
current=watts(power)/voltage
Power = volts times amps, so an appliance drawing 10 amps at a line voltage of 110 volts is consuming 1,100 watts. Keep in mind, however, that in a non purely resistive load, the phase angle of amps to volts might not be zero degrees, so the calculation becomes more complex, and depends on power factor, or phase angle.
You need to convert the voltage if your appliance requires less voltage than you power supply. example: appliances is 110V and power supply is 220V.
You just need the voltage and the current. Watts = Amps x Volts.
225W
No. You need a 3-phase supply that matches the voltage and current rating of your appliance.