First of all the power consumed is only dependent on the load (eg. any appliance) connected to the source. A load will always draw its rated power. If you have increased your voltage to twice then the current drawn by the device will become half but the power consumed will remain same.
the power consumed is given by:
P= V*I* cos(fi)
here for a given load P(power), cos(fi) are constants.
Then if V becomes 2V then current will be I/2.
It is halved. coz voltage=current * resistance
By Ohm's Law, current is voltage divided by resistance, so if you double both the voltage and the resistance, the current would remain the same.
The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.
A: Nothing will happen if the load increases or even removed the voltage will go to the open voltage condition no harm.
Using Ohms Law: V = I x R, where V (Voltage), I (Current), and R (Resistance). re-arranging: V/R = I Therefore if you double both the Voltage and the Resistance, the current remains unchanged.Current = Voltage / Resistance. If both resistance and voltage double the current remains the same.
It is halved. coz voltage=current * resistance
Ohm's law states that the voltage across a resistor is the product of the current times the Resistance or V=I x R (I times R). V is Voltage, R is Resistance, and I is Current or Amperage. So if the Voltage is doubled and Resistance stays the same, the Current will be doubled.
I = E/R If resistance is constant, then current is directly proportional to voltage. Double the voltage ===> the current will also double.
That has no effect on the resistance. The current doubles also.
double if resistance is considered same.
By Ohm's Law, current is voltage divided by resistance, so if you double both the voltage and the resistance, the current would remain the same.
by the ohms law we can clearly say that the current is the ratio of voltage to the resistance.as the resistance is doubled the current should be halved.
it will cause a Short Circuit
The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.
The current is doubled.I = V/RI=2V/RLets assign arbitrary numbers to voltage and resistance to evaluate what happens. Voltage will be 8 volts and resistance will be 2 ohms.I = 8/2 Therefore current = 4ampsIf voltage is doubled then,I =2(8)/2I=16/2I = 8 amps
If I0 = V/R, then Inew = (2*V)/(.5*R) = (2 / .5) * (V/R) = 4 *V/R = 4 * I0
The apmeres depend on the resistance of the circuit. The battery will be a certain voltage, and dividing the voltage by the resistance gives you amperes. V = I*R