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Pp x Pp yields PP, Pp, Pp, pp. PP is the only genotype which will cause the phenotypic expression of the gene - symptoms of PKU. Therefore the probability is 1/4 or 25%

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Q: If both heterozygous parents are carriers of a recessive allele for phenylketonuria the probability that a given child of these parents will have PKU is?
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Related questions

Why were heterozygous individuals called carriers for non-sex-linked and x-linked recessive patterns of inheritance?

I don't know and don't care


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Phenylketonuria (PKU) is inherited when both parents are carriers of the gene. Since it is a recessive gene, there is a 25% chance that any baby conceived by two people carrying the PKU gene will have PKU.


Condition of being heterozygous for a recessive trait?

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Is it true that people who are heterozygous recessive allele but who have a normal phenotype eill not pass the harmful recessive allele to their kids?

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I don't know and don't care


Why are heterozygous individual called carriers for non-sex-linked and x-linked recessive patterns of inheritance?

I don't know and don't care


What is it when you have a gene pair that consist of two dominate alleles and two recessive alleles?

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