The question is not formed well enough to answer it. The bandwidth of a medium is a frequency interval in which the medium is able to transmit information. So first we need a few more questions before we can answer.
The medium itself doesn't HAVE a frequency. So what is 100MHz? The frequency of the carrier signal? That's what I'm betting for. That data alone tells us absolutely nothing about the bandwidth. You need at least a transmission characteristic function to determine it.
The other possibility that the 100MHz is the bandwidth. In that case the bandwidth is 100MHz.
Solution Let fh is the highest frequency and fl is the lowest frequency. Bandwidth = fh - fl = 4000 - 40 KHz = 3960 KHz = 3.96 MHz
BW = (1 MHz - 10 KHz) = (1,000 KHz - 10 KHz) = 990 KHz
100MHz Wavelength(m) is inversely proportional to frequency (Hz) Use the equation λ=v/f (Wavelength=velocity/frequency) For the velocity just use the value 1 as since both waves will be through the same medium it doesn't matter 0.000001m = 1ms-1 / 10,000,000Hz 0.0000001m = 1ms-1 / 100,000,000Hz
Processor / bus frequency has no direct correlation to bandwidth.
Let's take an example. Suppose that the intermediate frequency is 10,7 MHz (FM). The local oscillator works on 110,7 MHz. First case: You receive a signal of 100 MHz, the mixer will generate a frequency of 110,7 + 100 = 210,7 MHz, which will be rejected by the band-pass filter. The difference of the two frequencies is 110,7 - 100 = 10,7 MHz (desired one). Second case: You receive a signal of 121,4 MHz. The sum of that frequency and the local oscillator is 232,1 MHz, which will be rejected. The difference is 121,4 - 110,7 = 10,7 MHz. So the image frequency in that case is going to be 121,4 MHz.
I came up with 14.8 khz, is this right?
To calculate the intermediate frequency (IF) for a radio receiver at 70 MHz, you typically choose a fixed IF value such as 455 kHz or 10.7 MHz. The IF frequency is chosen in such a way that when the desired signal frequency (70 MHz) is mixed with the local oscillator signal, it falls within the receiver's bandwidth for demodulation. This allows for effective filtering and processing of the signal at a manageable frequency before demodulation.
Modal bandwidth
Frequency = speed/wavelength = 300,000,000/3 = 100 MHz.
To convert MHz to Hz, you need to multiply the value in MHz by 1,000,000. For example, if you have a frequency of 100 MHz, the equivalent in Hz would be 100,000,000 Hz (100 x 1,000,000).
ISO/IEC 11801 defines several copper media classifications: Class A (up to 100 kHz), Class B (up to 1 MHz), Class C (up to 16 MHz), Class D (up to 100 MHz), Class E (up to 250 MHz), Class EA (up to 500 MHz), and Class F (up to 600 MHz). The classifications specify the maximum frequency bandwidth supported by the cabling system.
88 MHz-108MHz